Rxbenefits, inc. Interview Questions, Process, and Tips

7:3

suppose
pipe:
A -30 hours A’s effeciency (60/30) =2
60( lcm of 30 and 20)
B- 20 hours B’s effeciency (60/20)=3

time taken by both to fill = 60/5 =12 as given in question (effeciencies of both a+b =2+3=5)
time taken by faster pipe i.e b = 60/3 =20

75/8 days

3

This is more logical …

Let the 1st flag 1 placed at the origin ….
in crossing 8 flags he traveled 7 distances….
s=d/t
=7/8

time for 4 flags t=(d/s)=4/(7/8)=(4*8)/7=4.5714285714285714285714285714286

211

x+8y=20, x=-3y
(-3y)+8y=20
5y=20
y=4
The answer for y is 4

16, 28, 36

15%

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status after 3 games
A-40
B-40
c-80
d-16
status after 2 games
A-20
B-20
C-40
D-96
status after 1 game
A-10
B-10
C-108
D-48
status after 0 games
A-5
B-93
C-54
D-24
so answers are
a)A
b)B
c)93

Its very simple..
consider the fraction of s in the mixture = 1/3
So if we add one more R the the fraction wil be = 1/4
Automaticaly S becomes 25% of the mixture

2 minuts the speed ofthe train

0.000256