W R Berkley Interview Questions, Process, and Tips

60 liter

15km/hr

C.46
4+7
11+(7*2)
25+(7*2*2)
53+(7*2*2*2)
109+(7*2*2*2*2)…..

i will drop a mail saying that can you pleaae meal me the the originals of the stregic plan

890.488

temp at 3.oo pm is = 22.5
temp at 6.oo pm is = 30
thus, percentage rise= 7.5/30 *100
=25%

20

let,first num be x and second num be y
hcf =264
lcm=44
given equation
x/2=44 i.e x=88
product of 2 numbers is equal to lcm*hcf
88*y=44*264
y=132

That person’s struggle and dream to achieve something motivates the person.

c-> structured oriented lang
Pascal-> Procedure oriented lang

The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

20 minutes