TORII GRC Interview Questions, Process, and Tips

A.

$57.30

first 10 odd num are 1,3,5,7,9,11,13,15,17,19
sum=100
avg=100/10
avg of 10 odd num =10

S=D/T
S=624KM/6.5HRS
S=96KM/HR

Solution:

As given, we have,

The cost of one pen = 36 Rs.

So, the cost of 15 pens = 36 × 15 = 540 Rs.

The cost of one book = 45 Rs.

So, the cost of 12 books = 45 × 12 = 540 Rs.

The cost of one pencil = 8 Rs.

So, the cost of 10 pencils = 8 × 10 = 80 Rs.

Now,

the cost of each eraser is 40 Rs. less than the combined costs of pen and pencil.

So,

Combined costs of pen and pencil = 36 + 8 = 44 Rs.

Cost of one eraser = 44 – 40 = 4 Rs.

So, the cost of 5 erasers = 4 × 5 = 20 Rs.

Hence,

The total amount spent is

Hence, the total amount spent is 1180 Rs.

The number of ways of selecting a group of eight is
5 men and 3 women=5C5​×6C3​ =20
4 men and 4 women=5C4​×6C4​ =75
3 men and 5 women=5C3​×6C5​=60
2 men and 6 women=5C2​×6C6​=10
Thus the total possible cases is 20+75+60+10=165.

LET ACTUAL PRICE BE 100 RS(FOR CONVINIENCE)
THEREFORE IF PRICE IS CUT BY 20%
THEREFORE NEW PRICE=100-20=80 RS
THEREFORE WE NEED TO ADD X% TO 80 RS TO MAKE IT 20 RS AND ADD IT TO 80 TO MAKE IT 100RS
THEREFORE, 80X/100 = 20
I.E. 4X/5=20
THEREFORE x=20*5/4
=5*5
=25
HENCE 25% OF PRICE SHOULD BE ADDED TO MAKE THE PRICE EQUAL TO THE ACTUAL PRICE.

Mohammad Gauri

1600 years contain 0 odd day.
300 years contain 1 odd day.
94 years = (23 leap years + 71 ordinary years)
= (46 + 71) odd days
= 117 odd days, i.e., 5 odd days
Days from 1st January 1995 to 28th February 1995
= (31 + 28) days = 59 days
= (8 weeks + 3 days) = 3 odd days
∴ Total number of odd days
= (0 + 1 + 5 + 3) = 9 odd days i.e., 2 odd days.
So, the required day is Tuesday.

20- buy 15 books
15- buy 20 books

Original price is 20.

20

Let the journey distance be : x miles
Now x/40+x/30=8 (time=distance/speed)
Solving this for x we get. x=960/7
therefore, x=137(approx)
(137.14 exact)

2years