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The Ottawa Police Service (OPS) is the law enforcement agency responsible for providing policing services to the city of Ottawa, Ontario, Canada. With a mission to serve, protect, and safeguard the community, the OPS operates with a commitment to integrity, respect, accountability, and professionalism.
As one of the largest municipal police services in Ontario, the OPS employs a diverse team of sworn officers, civilian staff, and volunteers dedicated to maintaining public safety and promoting community well-being. The service is organized into various units and divisions, including patrol, criminal investigations, traffic enforcement, community policing, and specialized units such as K-9, tactical, and cybercrime.
In addition to their primary role of law enforcement, the OPS is actively involved in community engagement initiatives aimed at building trust and fostering positive relationships with residents, businesses, and community organizations. This includes outreach programs, public education campaigns, and collaborative efforts with other agencies and stakeholders to address issues such as crime prevention, substance abuse, and mental health.
The Ottawa Police Service is committed to upholding human rights, diversity, and inclusion in all aspects of its operations. It strives to reflect the diverse population it serves and to ensure fair and equitable treatment for all individuals, regardless of race, ethnicity, religion, gender, or socio-economic background.
Overall, the Ottawa Police Service plays a vital role in ensuring the safety and security of the nation's capital and its residents, working tirelessly to uphold the rule of law and contribute to the well-being of the community.
Ans: 60 kph
Suppose Person meets the train everyday at 3 PM at Station A.
His speed is 12kph.
So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.
But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.
Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.
So speed of the train is 5KM/5min = 60 kph.
Let’s say, length of train = x metres
Speed at pole = Speed at platform
x/15 = 100+x / 25
5x = 300 + 3x
2x = 300
x = 150m
So, train is 150 metres long.
as total 16 floors out of them 11 were rented to A and B company .So remaining floors are 5 and each floor is 12000s.ft
So remaining = 12000*5
=60000
5c2*4c1/9c3 +5c3/9c3=25/42
The answer for this question is very simple: it is called Ceaser Cipher.
It consists of replacing a character by another located in (current character position + (key-1)), where key = how many positions you want to skip.
For Example: VICTORY -> YLFWRUB with the key = 3.
Then SUCCESS -> QXFFHQQ
Note: it should work like a circle(Z+1 = A).
twenty members
30mins
Let the total time taken to fill the tank be x minutes.
Then, work done by B in half hour + work done by (A+B) in half hour =1.
(
40
1
×
2
x
)+(
60
1
+
40
1
)×
2
x
=1
⇒
80
x
+
48
x
=1
⇒
240
3x+5x
=1
⇒8x=240
⇒x=30 min
Ratio of diameters=1:2
Ratio of radius=1:2
Ratio of volumes=(4/3*3.14*r1^3)/(4/3*3.14*r2^3)
=r1^3/r2^3=1^3/2^3=1/8