Recent Answer : Added by soni On 2022-10-21 19:49:18:
1506
Ques:- A train 240 m in length crosses a telegraph post in 16 seconds. What is the speed of the train ?
Recent Answer : Added by jay On 2022-03-09 16:41:09:
speed = distance / time.
240/16=15m/sec=54km/hr
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Ques:- The time taken by a train 180 m long, travelling at 42 kmph, in pasing a person walking in the same direction at 6 kmph, will be
A. 16 sec
B. 18 sec
C. 21 sec
D. 24 sec
Recent Answer : Added by SHOWMINI R On 2022-08-14 16:29:07:
D = 180m
S = 42 – 6 = 36 * 5/18 = 10
T = D/S = 180/10
T = 18s
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Recent Answer : Added by SOMASKANDHAN V On 2022-09-22 16:39:29:
Reading your question
Ques:- India : New Delhi : : Pakistan : ?
A. Lahore
B. Islamabad
C. Peshawar
D. Rawalpindi
Recent Answer : Added by Admin On 2020-05-17 12:03:24:
the capital of India is New Delhi
the capital of Pakistan is Islamabad
the ans is(b)Islamabad
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Ques:- Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in?
Recent Answer : Added by M.N On 2021-04-05 14:58:46:
3×8=24=2xt ===> t=12hours
Ques:- An amount of Rs. 3000 becomes Rs. 3600 in four years at simple interest. If the rate of interest was 1% more, then what was be the total amount?
Recent Answer : Added by Sakshi On 2021-08-08 09:30:35:
3606
Ques:- Tell me about summer training in B.Tech 2nd yr with Computer Science?
Ques:- A car travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs.What is the distance travelled
A. 210 kms
B. 30 kms
C. 20 kms
D. none of these
Recent Answer : Added by Michael Torcaso On 2022-08-14 16:28:58:
Let d = 7r. And use distance is = rate × time
7r= ( r+12) 5
7r= 5r + 60
Subtract 5r from both sides
2r = 60
Divide out 2
Rate = 30 km/h
Original question 30 km/h × 7 = 210
30 +12 = 42× 5 = 210
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Ques:- 1. A plane travels 695km with wind and 498km aginst the wind in same time.The speed of wind is 21km/hr. Find the speed of plane?
Recent Answer : Added by Admin On 2020-05-17 12:01:01:
127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)
1506