Answer:
11 days.
Step-by-step explanation:
In the question,
Time taken by Ramesh to finish a piece of work = 20 days
Time taken by Sushil to finish a work = 25 days
Time for which they worked together = 5 days
Sushil left after = 5 days
So,
One day work of Ramesh is,
One day work of Sushil is,
So,
Work done in 5 days is given by,
Therefore, Remaining work is given by,
Now, as the Sushil left the remaining work was done by Ramesh,
Time taken by Ramesh for the remaining work is,
Therefore, the remaining work will be completed in 11 days by Ramesh.
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
d
T=Distance/speed
T=(150+200)/(120×5/18)
answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x+602) hrs and
Time needed to reach the station at 4 km/hr = (4x+602) hrs But 3x+301=4x−301⇒3x−4x=−302=151
⇒124x−3x=151⇒12x=151⇒x=1512=54 km
( b ) 40 sq cm
P Q R S
TP -> UQ -> RV -> SW
Answers-
U sits opposite to S
Q sits in between S and R (after interchange)
list price – actual price markrd by the company
net price (average price of all items inclusive all discounts,breakage & so on.) which is 425 i.e. 50% of the marked price
hence the list price or marked price is twice the net sale price = 850
50%=425
100%=?
=100%*425/50=850
40
simple logic, Check Option Lets father present age = 40 so it full fill all condition like his son age become 10 and after five years it will become 15 and father age is 45 and it full fill second condition that fathers age is thrice as old as the son after 5 years
0
say the work is w and let no of days taken by b is ‘x’ which
we have to calculate
so work done by a in one day is w/6
work done by b in one day is w/x
a and b together can do work in 4 days ie=(w/6)+(w/x)=(w/4)
solving equation x=12
so no of days taken by b=12
20&130
20- buy 15 books
15- buy 20 books
Original price is 20.
Days taken by A to complete whole work= 140 days
Days taken by B to complete whole work= 105 days
A’s 1 day work= 1/140
B’s 1 day work= 1/105
On adding these together we get: 1/60 (1 day work by working together)
So, together they will be able to complete it in 60 days