Logix federal credit union Interview Questions, Process, and Tips

Prob(choosing two people who are a couple from 6 couples) = 1/6
We have 5 couple left (10 people)
Prob(choosing a person A from 10 people) = 1/10
Prob(choosing 1 person who is not a couple of A) = 1/8

Prob(choosing 4 people that has exactly one couple) = 1/6*1/8*1/10 = 0.0021

c=a/b
c=a-1
=>b=a/c
=>b=a/a-1

D.12

22

1

Either 4 or (-)4

39 hrs 15 mins..
note:
he will not be having .45 mins for his lunch on saturday..

1/24-1/40
(5-3)/120
2/120
1/60
60 minutes

A’s speed=6 mph ,B’s speed=8 mph
Let, after x hrs, they will meet.
so, the distance traveled by A in x hrs should be the same as the distance traveled by B in (x-1/2)hrs [as B started the journey after 30 min of A]
Thus, 6x=8(x-1/2)[as distance=speed*time]
=>8x-6x=4
=>2x=4
=>x=2
after 2 hrs they will meet so time=(9+2)=11.00 a.m

(T-P)-(U-Q)-(V-R)-(W-S)
S Opposite is Q
U sits the P and Q

The probability will be
white ball = 5/9
red ball = 4/9
The answer can be 5/9 and 4/9 or 1

127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)