20 minutes
There are 18 numbers between 100 and 300 that are divisible by 11: 110, 121, 132, 143, 154, 165, 176, 187, 198, 209, 220, 231, 242, 253, 264, 275, 286, 297.
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The batsman on 98 is on strike. He hits the ball and they run 3. UNFORTUNATELY one of the batsmen doesn`t turn correctly for one of the runs and the umpire calls ONE SHORT and awards only two runs. Therefore the first batsman has his century. There is now 1 ball remaining and one run is required to win. The batsman on strike, however is now the one on 97 runs. He now either hits a 4 or a 6. They win the game and both batsmen scored centuries.
Read more: 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries … – 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries as well win the match ?
5, 16, 6, 16, 7, 16, 9
d
16, 28, 36
ans: 40
6/3*12/3*15/3=40
Total inversement =20000
Arun and vinay =40% ,40%
Kamal =20%
8 month gain = 4005
Arun and vinay share of 6 months=1201.5
Kamal share of 6 month = 600.75
Now Arun left, then remaining 2 month’s profits =1001.25
In this case kamal have 33.3% and vinay have remaining percentage of 1001.25
33.3% of 1001.25 is 333.4
Now, total share of kamal is 600.75+333.4=934.16
Answer: 450
Explanation:
10 * 150 = 1500
3 * 100 + 5 * 150 = 1050
1500 – 1050 = 450
The first number is 36
Step-by-step explanation:
let their common factor be ‘x’
hence,
the ratio be 3x/5x
hence, by condition;
(3x-9)/(5x-9)=9/17 ch upu
9(5x-9)=17(3x-9)
45x-81=51x-153
153-81=51x-45x
72=6x
x=72/6
x=12
the first number is 3x=3×12=36
6.25
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five multiplication & three addtion