Ques:- A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken?
Recent Answer : Added by N On 2021-05-18 10:48:11:
time is inversely proportional to speed.
So if speed taken is 4/5 of usual speed, time taken will be 5/4 of usual time
and the difference between time is 10 min
So,
(5/4)t -t=10 min
usual time,t=40 min
late time=40+10=50 min
Ques:- consider expresion ‘ab’ . what happens when ‘a’ is divided by ‘c’ & ‘b’ is multiplied by ‘c’.
Recent Answer : Added by Admin On 2020-05-17 11:59:58:
value remains same
Ques:- Perimeter of the back wheel = 9 feet, front wheel = 7 feet on a certain distance, the front wheel gets 10 revolutions more than the back wheel .What is the distance?
Recent Answer : Added by Admin On 2020-05-17 12:04:03:
Let the revolutins made by bigger wheel is: x
then revolution by smaller wheel will be: x+10
Now, the distance covered by both wheels will be same.
So,
7(x+10)=9x
7x+70=9x
70=2x
35=x
so distance travelled=9*35=315
or 7*45=315
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Ques:- burns caused by steam are more severe then burns by hot water.wahy?
Recent Answer : Added by Admin On 2020-05-17 12:04:04:
coz steam has more heat content than hot water
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Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
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Recent Answer : Added by Admin On 2020-05-17 11:59:23:
9
Ques:- A driver drives at a speed of 72kmph in a highway. Another driver drives at the speed of 25 m/sec . find the difference in their speeds in m/sec. ?
Recent Answer : Added by Admin On 2020-05-17 12:04:21:
5m/sec
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Ques:- Sum of two numbers is 80. Greater number exceeds by 5 from four times of the smaller. Find the numbers?
Recent Answer : Added by Admin On 2022-09-29 18:30:23:
Let x and y be the two numbers. And x > y.
Then,
x + y = 80—–(1)
y=80-y
Also,
x = 4y – 5
Solving the two equations,
80 – y = 4y – 5
85 = 5y
Therefore, y = 17
put the value of y in equation(1)
then
x+y=80
x+17=80
x=63
the numbers are 17&63
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Recent Answer : Added by Admin On 2020-05-17 12:02:31:
120 (5×4!)
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Recent Answer : Added by Shweta Gupta On 2022-09-02 17:03:06:
Sunday
Monday
Tuesday
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Recent Answer : Added by Anonymous On 2021-08-11 07:22:43:
5x/4
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time is inversely proportional to speed.
So if speed taken is 4/5 of usual speed, time taken will be 5/4 of usual time
and the difference between time is 10 min
So,
(5/4)t -t=10 min
usual time,t=40 min
late time=40+10=50 min