Sphera Interview Questions, Process, and Tips

Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1​ cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2​ i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61​,P(B)=61​,P(C)=65​,P(A)=61​,P(B)=65​,P(C)=61​ and P(A)=65​,P(B)=61​,P(C)=61​
Hence the required probability = 61​×61​×65​×6×3=21690​=125​

( e ) Apple

there will be no banana left

B

Matches played: 60.
Matches won: 30% of 60 => (60*(30/100)) = 18 matches.
Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
20 / 62 = 0.3225806451612903
21 / 63 = 0.3333333333333333
22 / 64 = 0.34375
…
…
…
…
Similarly,
41 / 83 = 0.4939759036144578
42 / 84 = 0.5

So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.

They will meet at the center of the square…as the
direction vector of all the ants/people change according to
the first person.
The independent path of each person taken will be spiral in
nature.

C

1 – (-1) = 1 +1 = 2

3×8=24=2xt ===> t=12hours

8400 ? 120 x 15 + 150 = ?
ans:
8400 % 120 x 15 + 150 = ?
1200

15%

6+8+10+10= 36
6²+8²+10²+12²=344

21 days

79