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A. Rs 140
7+8+11=26
B: 7/26*520= 140
8 cubes
125^15 would be 5^18
625^20 would be 5^24
25^10 would yield 5^12
so
The answer is b) i.e. 5^125
4
X+x+2+x+3=42
3x+6=42
3x=42-6=36
X=12
X+2=14
X+3=15
Middle number 14
237.6 Kmh
time = distance / speed
speed = 36*(5/18) m/s=10m/s
distance = 100m
time=100/10s = 10sec
Fathers before age=3*before sons age—-(1)
After 2.5 years..
Fathers before age+2.5 years =2.5*sons age—-(2)
Substitute (1) in (2),
3*sons before age+2.5 years=2.5*sons age
0.5*sons age=2.5 years
Sons before age=5years
So current age after 2.5 years,
Sons before age+2.5 =5+2.5=7.5 years
The batsman on 98 is on strike. He hits the ball and they run 3. UNFORTUNATELY one of the batsmen doesn`t turn correctly for one of the runs and the umpire calls ONE SHORT and awards only two runs. Therefore the first batsman has his century. There is now 1 ball remaining and one run is required to win. The batsman on strike, however is now the one on 97 runs. He now either hits a 4 or a 6. They win the game and both batsmen scored centuries.
Read more: 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries … – 3 runs required in 3 balls to win with only a wicket left. The batsmen is on 98 and the runner is on 97. How will both the batsmen score centuries as well win the match ?
one cat kill one rat six minutes
so 1 cat kill 100 rat willbe needed 6*100=600minutes
then 100 rates kill 50minutes means then 600/50=12
so the answer is 12
200/3
15/46=0.32
5m/sec
Correct option is C)
Let be students are consider as child
Let the age of child added later be x years.
average age of 12 children =20 years
∴ Total age of 12 children =20×12=240 years
After one more child is added-
Average of 13 children =20−1=19 years
Average age of 13 children =
13
sum of 12 children+x
19=
13
240+x
⇒240+x=247
⇒x=247−240=7 years
Hence the age of child added later is 7 years.