Dubai holding group Interview Questions, Process, and Tips

let,first num be x and second num be y
hcf =264
lcm=44
given equation
x/2=44 i.e x=88
product of 2 numbers is equal to lcm*hcf
88*y=44*264
y=132

444km
Since the speed diff is 5km/h
It takes 12 hrs to cover 60 extra kms
Therefore in 12 hrs the total dist covered is
Relative speed×time=(21+16)×12=444 kms

let x be the avg age of each person in the family ten years
back…
so total age=6x
after 10 years i.e,now the total age of the family =6x+60
let grand father age as y
then the average of the family=(6x+60-y)/5
(bcoz grand father has expired and the new born baby has no
age at present)
according to the given question (6x+60-y)/5=x
bcoz x is the avg age bfore 10 years.
while calc the equation according to the presnt age we have
to add 10 to the result….
so the answer is 70

125^15 would be 5^18
625^20 would be 5^24
25^10 would yield 5^12
so
The answer is b) i.e. 5^125

Let cost for apple be a Cost for banana be b and Orange be c

So by first value expression becomes 17a + 13b + 9c =130 ———-1 therefore if you further solve a = (130 – 13b – 9c)/17 ———- 2 the second expression becomes: 13c + 7a + 10b = 100 ———- 3 If you put value of a in second expression it becomes: 13c + 7[(130 – 3b – 9c)/17] +10b = 100

Further if you solve you get value of b:

b = 10 – 2c ———-4

put value of b from 4 in 1

17a + 13 [10 – 2c] + 9c = 130

Further if you solve you find value of a

a = c ———-5

Put 5 in 3

13c + 7c + 10b = 100

further solve you get: c = 1 ———-6

from 5 and 6

a = c = 1 ———-7

Substitute value of c in expression 4

b = 10 – 2c b = 10 -2 * 1 b = 8 ———-8

therefore a + b + c = 10

38 years

Let Rajan’s present age be x years. Then, his age at the time of marriage = (x – 8) years.

x = 65(x−8)

⇒5x=6x−48

⇒x=48 years

Rajan’s sister’s age at the time of his marriage = (x – 8) – 10 = (x – 18) = 30 years

∴ Rajan’s sister’s present age = (30 + 8) years = 38 years

let the total work to be done =1
so a+b+c=1 (say)
then a and b are supposed to do 7/11 th of work
so c= 1- (7/11)
c=4/11
therefore c gets (4/11)*550
=200 is the answer

((15 X m) + 23)/(m+1)= 16
solving , we get number of matches (m) as 7 (excluding last
match)
so he shud hit 39 runs in last innings to ake average to 18