Ques:- Which greatest number will divide 3026 and 5053 leaving remainders 11 and 13 respectively?
A. 15
B. 30
C. 40
D. 45
Recent Answer : Added by Vijay Vinod On 2022-09-16 14:52:15:
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
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Recent Answer : Added by Admin On 2020-05-17 12:02:01:
If the bell rung when they r started is also counted then it
will be 5 otherwise 4
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Recent Answer : Added by Suman On 2021-10-07 15:41:23:
Matches played: 60.
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Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
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…
…
…
…
Similarly,
41 / 83 = 0.4939759036144578
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3630
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4
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Y filling rate is 1/24 or 3/72 per hour
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125
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A
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Ques:- There are twelve consecutive flags at an equal interval of distance. A man passes the 8th flag in 8 seconds. How many more seconds will he take to pass the remaining 4 flags?
Recent Answer : Added by DK BOSS On 2021-07-17 06:40:10:
This is more logical …
Let the 1st flag 1 placed at the origin ….
in crossing 8 flags he traveled 7 distances….
s=d/t
=7/8
time for 4 flags t=(d/s)=4/(7/8)=(4*8)/7=4.5714285714285714285714285714286
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45