East
In the example first we have to find the area of the field
we have given the following values ,
cost of fencing per meter = Rs 1.50
Diameter of circular field = 28
We have to find the area , a = ?
We know that,
Area = 2 π r
= 2 x 22/7 x 14
= 2 x 22 x 2
= 44 x 2
= 88 sq. m
So, area of circle is 88 sq.m
Now just multiply it with 1.50
cost of fencing = 88 x 1.50
= Rs. 132
So, the cost of fencing the circular field is Rs. 132
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divisible by 8 – 124
” 12 – 83
” both – 41
124 + 83 – 41 = 166
999 – 166 = 833
ans is 833…..
414 Rs
1.2*37.8=45.36=46 sq.feet
46*9=414 RS
24
500
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Example 1:
Assign, A=20, B=10, C=5, D=5(Because C is equal to D as
given), E=1.
A/B = 20/10 = 2. So A/B = 2
A/C = 20/5 = 4. So A/C = 4
A/E = 20/1 = 20. So A/E = 20
Therefore “A/E is Greatest”
Example 2:
Assign, A=100, B=50, C=20, D=20(Because C is equal to D as
given), E=10.
A/B = 100/50 = 2. So A/B = 2
A/C = 100/20 = 5. So A/C = 5
A/E = 100/10 = 10. So A/E = 10
Therefore “A/E is Greatest”
1/221
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8, 7, 11, 12, 14, 17, 17, 22, (…..)
20
P Q R S
TP -> UQ -> RV -> SW
Answers-
U sits opposite to S
Q sits in between S and R (after interchange)
the sum of first 4 primes numbers =2+3+5+7 =>17