Royal australian navy Interview Questions, Process, and Tips

find out what is the problem and taking the bad out always works.

Explanation:

72 — 9
? —- 1

=> Down Stream = 8

45 —- 9
? —- 1

=> Up Stream = 5

Speed od current S = ?

S = (8 – 5)/2 = 1.5 kmph.

let t = total no of students.. then
students who passed one or both subjects,
n(e U h) = n(e) + n(h) – n(e intersection h)
=> t = 0.8t + 0.7t – 144
=> t = 1.5t – 144
students who failed both subjects is 10% i.e. 0.1t
=>t-n(e U h) = 0.1t,
=>t -(1.5t – 144) = 0.1t
=>t- 1.5t- 0.1t = -144
=> -0.6t = -144
=>t = 240

Green bricks

20

One day’s work of A, B and C = (1/24 + 1/30 + 1/40) = 1/10.

C leaves 4 days before completion of the work, which means only A and B work during the last 4 days.

Work done by A and B together in the last 4 days = 4 (1/24 + 1/30) = 3/10.

Remaining Work = 7/10, which was done by A,B and C in the initial number of days.

Number of days required for this initial work = 7 days.

Thus, the total numbers of days required = 4 + 7 = 11 days.

let x be sum.
SI of 18% for 1 year= x*18/100=0.18x;
SI of 18% for 2 years is 0.36x;

SI of 12% for 1 year= x*12/100=0.12x;
SI of 12% for 2 years is 0.24x;

Given, 0.36x-0.24x=840
0.12x=840
x=840/0.12=7000.

At 130 years.

4

Its 2 times faster than the other train
v1*t=v2
v2*t=4*v1
solving these two,we get
v2/v1=2

21

10 x 27=270

₹1 today increases to (1+1/8) = 9/8 after 1year.

After 2 years it increases to 9/8 of 9/8 = (9/8)^2 =81/64 times.

Hence ₹64000 increase to 64000×81/64 =₹81000

If division of 3 is allowed then I might do 5 divisions in one go & do in less iterations. I would assume max 2 division as you have to hands, and compare the weight.

ans: .1432 inch
1-3/4=1/4
1-1/12=11/12
1/8,1/4,11/12 are broken off
so
5/8
5/8/4
5*11/8/4/12
remaining .1432inch

1/8

d