Rk management consultants, inc. Interview Questions, Process, and Tips

let MP = 100x
25% discount = 75x -> SP
Profit% = (Profit/CP)x100
125 = (75x/CP)x100
.: CP = 60x

Now if discount = 10%
SP = 90x
.: Profit% = ((90x-60x)/60x)x100 = 50%

20kmph

Given:

In a group of 15 students,

7 have studied Latin,

8 have studied Greek,

3 have not studied either.

To find:

The number of students who studied both Latin and Greek.

Solution:

In a group of 15 students, have studied Latin, 8 have studied Greek, 3 have not studied either.

Therefore,

n(A∪B) = 15 – 3

n(A∪B) = 12

7 have studied Latin,

n(A) = 7

8 have studied Greek,

n(B) = 8

n(A∩B) is the number of students who studied both Latin and Greek.

n(A∩B) = n(A) + n(B) – n(A∪B)

n(A∩B) = 7 + 8 – 12

n(A∩B) = 15 – 12

n(A∩B) = 3

The number of students who studied both Latin and Greek is 3

Final answer:

3 of them studied both Latin and Greek.

Thus, the correct answer .3

MBA refers to Master Of Business application, so that the line says as well our day to day life is also consider as an business, and second by science stream but why not in other, it depends on the capacity of student and smart move kind off.

1 1 2+4
2 2 1+4
3 1+2 4
4 4 1+2
5 4+1 2
6 4+2 1
7 4+2+1 0

these r all factors of 30
1*30=30
2*15=30
3*10=30
5*6=30
like that

2cm b)

let a = 9 * 9 * 9;
let b = 12 * 12 * 12;
let c = 15 * 15 * 15;

sum = a + b + c;

edge = Math.cbrt(sum);

console.log(edge);

1896172

C)1440
2*2=4
4*3=12
12*4=48
48*5=240
240*6=1440

523

There are 18 numbers between 100 and 300 that are divisible by 11: 110, 121, 132, 143, 154, 165, 176, 187, 198, 209, 220, 231, 242, 253, 264, 275, 286, 297.

C

10%=394;50%=1970;250%=9850;30%=1182;
250%+30%=9850+1182=11032