Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:40:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;
Ques:- Number Series 19,24,20,25,21,26,?
Recent Answer : Added by Boomika On 2022-05-17 09:09:03:
22
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Ques:- If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
Recent Answer : Added by Admin On 2022-09-29 16:36:42:
answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x+602) hrs and
Time needed to reach the station at 4 km/hr = (4x+602) hrs But 3x+301=4x−301⇒3x−4x=−302=151
⇒124x−3x=151⇒12x=151⇒x=1512=54 km
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A. 1001
B. 1003
C. 1009
D. 1007
Recent Answer : Added by Akinwunmi Gbemisola On 2022-05-17 09:08:46:
A
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Recent Answer : Added by Rajeswari Suresh On 2021-10-10 19:03:43:
5c2*4c1/9c3 +5c3/9c3=25/42
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Ques:- The letters A, B, C, D, E, F and G, not necessarily in that order, stand for seven consecutive integers from 1 to 10 D is 3 less than A B is the middle term F is as much less than B as C is greater than D G is greater than …
Recent Answer : Added by DK BOSS On 2021-07-16 09:52:58:
Question is not completed
The letters A, B, C, D, E, F and G, not necessarily in that order, stand for seven consecutive integers from 1 to 10
D is 3 less than A
B is the middle term
F is as much less than B as C is greater than D
G is greater than F
1. The fifth integer is
(a) A
(b) C
(c) D
(d) E
(e) F
ans:a
2.A is as much greater than F as which integer is
less than G
(a) A
(b) B
(c) C
(d) D
(e) E
ans:a
3. If A = 7, the sum of E and G is
(a) 8
(b) 10
(c) 12
(d) 14
(e) 16
4. An integer T is as much greater than C as C is
greater than E. T
can be written as A + E. What is D?
(a) 2
(b) 3
(c) 4
(d) 5
(e) Cannot be determined
ans:a
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Ques:- A train 132 m long passes a telegraph pole in 6 seconds. Find the speed of the train
A. 70 km/hr
B. 71 km/hr
C. 72 km/hr
D. 79.2 km/hr
Recent Answer : Added by ABC On 2022-09-15 16:37:12:
79.2
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8
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Recent Answer : Added by shivangi sharma On 2022-08-14 16:42:35:
the ratio of present age of x:y is 5:6
And,we have to find the present age of x.
so,the present age of X is definitely will be multiple of 5.
X=35
so,35 is the answer.
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A. 30
B. 33
C. 36
D. none of these.
Recent Answer : Added by sangeetha On 2022-08-14 16:41:56:
33
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Recent Answer : Added by DIPALI On 2022-05-17 09:08:44:
A will finish work in 8 days (4days with B and 4 days with C).
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Recent Answer : Added by Rama Kiran On 2020-10-19 17:08:43:
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;