Orange and bronze software labs Interview Questions, Process, and Tips

( C ) Crawl

2 minuts the speed ofthe train

let,first num be x and second num be y
hcf =264
lcm=44
given equation
x/2=44 i.e x=88
product of 2 numbers is equal to lcm*hcf
88*y=44*264
y=132

Pfull = 4 Hrs; Qfull = 5 Hrs
Assume velocity Vp = x then Vq = 4/5 x –> avg velocity = (5/5 + 4/5) / 2 = 0.9
If fastest time = 4hrs then the time it would take to fill up tank by alternating is 4/0.9 = 4.44 Hrs

1728

4x:5x:6x
100:50:25
100×4x +50×5x+25×6x
then 400x + 250x + 150x = 16000
800x=16000
x = 20

25 paisa=6x = 20×6=120

so the ans is 120 coins

2.01%

8*1024+3*64+3
8192+192+3
8387
1000/0011/1000/0111
So ie 7. 1s here

Answer: 1 / 3

Lets say each brand had 16 laptops
So Sold : A = 3 , B= 1 and C = 12 , total sold: 16 ,
Since each brand has 16 , total = 48
so 16/ 48 = 1/3 is the sold fraction

Ans :15
X be a present age of mudit
After 18 year age of mudit is X+18
4 year ago age was X-4
As per question,
X+18=3(X-4)
X+18=3X-12
3X-X=18+12
2X=30
X=15

She is My grandmother

A control using ActiveX technologies. An ActiveX control
can be automatically downloaded and executed by a Web
browser. ActiveX is not a programming language, but rather
a set of rules for how applications should share
information. Programmers can develop ActiveX controls in a
variety of languages, including C, C++, Visual Basic, and
Java.

Relative speed = 60 + 90 = 150 km/hr.

= 150 x 5/18 = 125/3 m/sec.

Distance covered = 1.10 + 0.9 = 2 km = 2000 m.

Required time = 2000 x 3/125 = 48 sec.

1(100-1)+ 2(100-2)+…..99(100-99)
N=100
solution: N(N-1)
100(99)= 9900

Fathers before age=3*before sons age—-(1)
After 2.5 years..
Fathers before age+2.5 years =2.5*sons age—-(2)
Substitute (1) in (2),
3*sons before age+2.5 years=2.5*sons age
0.5*sons age=2.5 years
Sons before age=5years
So current age after 2.5 years,
Sons before age+2.5 =5+2.5=7.5 years