Ques:- You have not been to core accounting
Ques:- X^(1/3) – X^(1/9) = 60 Solve for X
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Ques:- Tell me about summer training in B.Tech 2nd yr with Computer Science?
Ques:- Briefly describe your ideal job?
Ques:- What is your febrate song and actors.
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Ques:- Two trains of equal length when moving in opposite direction takes 5 sec. to cross each other completely and when moving in same direction takes 15 sec. Find the ratio of their speed.
Ques:- The average age 9 members of a committee are the same as it was 2 years ago, because an old number has been replaced by a younger number. Find how much younger is the new member than the old number?
Ques:- Complete the series. 1/2, 3/4, 5/8, 7/16, ?
Recent Answer : :
9/32
Ques:- LCM and HCF of two numbers are 48 and 8 respectively. If one of the numbers is 16, the second number is
A. 36
B. 24
C. 18
D. 12
Recent Answer : :
ANS = 24.
16 = 2^4
24 = 2^3 x 3
H.C.F of 16 and 24 = 8
L.C.M will be 48
Ques:- What is spel of committee
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Ques:- Rs. 800 becomes Rs. 956 in 3 years at a rate of S.I. If the rate of interest is increased by 4%, what amount will Rs. 800 become in 3 years?
Recent Answer : :
1052
Ques:- Find out the wrong number in each sequence:
36, 54, 18, 27, 9, 18.5, 4.5
36, 54, 18, 27, 9, 18.5, 4.5
A. 4.5
B. 8.5
C. 18.5
D. 18
Recent Answer : :
C
Ques:- P, Q and R completed a piece of work, P worked for 6 days, Q for 9 days and R for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of R, if their total earning was Rs.1480?
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Ques:- Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?
Recent Answer : :
Marks in thrice in english as in science
so if science marks is x
then english marks = 3x
lets maths marks = y
ratio of english and maths marks is
3x/y = 3/5
=> y = 5x
and total marks = 162
3x + x + 5x = 162
x = 18 —-answer
Ques:- A>B, B>C, C=D, D>E, then which is greatest
Recent Answer : :
Example 1:
Assign, A=20, B=10, C=5, D=5(Because C is equal to D as
given), E=1.
A/B = 20/10 = 2. So A/B = 2
A/C = 20/5 = 4. So A/C = 4
A/E = 20/1 = 20. So A/E = 20
Therefore “A/E is Greatest”
Example 2:
Assign, A=100, B=50, C=20, D=20(Because C is equal to D as
given), E=10.
A/B = 100/50 = 2. So A/B = 2
A/C = 100/20 = 5. So A/C = 5
A/E = 100/10 = 10. So A/E = 10
Therefore “A/E is Greatest”
Ques:- Two chords of lengths 2L1 and 2L2 are drawn in a circle. Their lengths are inversely proportional to the straight distance joining the centre.Find the radius of circle?
Recent Answer : :
10m
Ques:- Pipe A can fill a tank in 6 hours. Due to a leak at the bottom, it takes 9 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
Ques:- The present ages of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages.
Recent Answer : :
16, 28, 36
Ques:- How do u maintain a mobile store with ur team members
Let’s assume the length of each train is ‘L’ and the speeds of the two trains are ‘V₁’ and ‘V₂’ respectively.
When the trains are moving in the opposite direction, their relative speed is the sum of their individual speeds. The total distance they need to cover is the sum of their lengths. Since they cross each other completely in 5 seconds, we can set up the following equation:
(V₁ + V₂) × 5 = 2L
When the trains are moving in the same direction, their relative speed is the difference between their individual speeds. The total distance they need to cover is the difference between their lengths. Since they cross each other completely in 15 seconds, we can set up the following equation:
(V₁ – V₂) × 15 = 2L
Now, let’s solve these equations to find the ratio of their speeds.
From the first equation, we have:
(V₁ + V₂) × 5 = 2L
V₁ + V₂ = (2L) / 5
From the second equation, we have:
(V₁ – V₂) × 15 = 2L
V₁ – V₂ = (2L) / 15
Let’s add these two equations together:
V₁ + V₂ + V₁ – V₂ = (2L) / 5 + (2L) / 15
2V₁ = (6L + 2L) / 15
2V₁ = (8L) / 15
V₁ = (4L) / 15
So, the speed of the first train is (4L) / 15.
Now, let’s substitute this value back into the first equation to find V₂:
(4L) / 15 + V₂ = (2L) / 5
V₂ = (2L) / 5 – (4L) / 15
V₂ = (6L – 4L) / 15
V₂ = (2L) / 15
Therefore, the speed of the second train is (2L) / 15.
The ratio of their speeds is given by:
(V₁ / V₂) = ((4L) / 15) / ((2L) / 15)
(V₁ / V₂) = 4L / 2L
(V₁ / V₂) = 2
So, the ratio of their speeds is 2:1.