A. Christian Dior
150 m
50 each
3x -y = 100
4x-2y = 100
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Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south
Options:
A) EDRIRL
B) DCQHQK
C) ESJFME
D) DEQJQM
Ans: A)
3*2-1=5
5*2-2=8
8*2-3=13
13*2-4=22
22*2-5=39
39*2-6=72
so series is 3,5,8,13,22,39,72
24 should be replaced by 22
24 is wrong…….
1972
let x=speed
t=time taken when speed is x so…
xt=4/5x(t+40)
t=160 minutes
2 hr 40 minutes
1(100-1)+ 2(100-2)+…..99(100-99)
N=100
solution: N(N-1)
100(99)= 9900
c
1896172