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What was his salary to begin with?
9, 11, 15, 23, 39, ?
71
Number of students behind Aruna in rank = (46 – 12) = 34. So, Arun is 35th from the last
let the 4 digit number be ABCD.
First Digit is A :
Therefore; according to the question
A=B/3
B=3A
C=A+B=A+3A=4A
D=3B=3(3A)=9A
Since the last Digit is D and it can neither be double-digit nor 0 ;
Therefore ;
A=1;
B=3A=3(1)=3
C=A+B=1+3=4
D=9A=9(1)=9
Therefore, the 4 digit number is 1349.
Kisan Baburao Hazare
ans is C.
let H be present age of husaband.W be present age of wife.
H+W=91.
now let diff between their ages be x.that is H-W=x.
now when husband is W yaers old, his wife must be W-x years
old.and it is given that H=2(W-x). so 2W-H=2x. and H-
W=x.eliminating x we get 4W=3H. but H+W=91, so solving thse
two H=52 W=39.
Ramu’s Mother-in-law means Ramu’s wife’s mother
Only daughter means Ramu’s wife
And daughter’s son means Ramu’s Son
Answer : Son
c=a/b
c=a-1
=>b=a/c
=>b=a/a-1
dividend=divisor*quotient+remainder
x=1000*(2*(110))+30
x=22000+30
x=22030
it is based on the right shift operation on the perticular digit
500 = Total+50
Total(450) = only one paper(p) + 29+20+35 + all three (g)
285+212+127 = p + 2( 29+20+35 )+ 3g
solve above .. to get g = 45 …
( small corrctn .. i think .. questn shud be 20 read ONLY
hindu and
times of India and 29 read ONLY hindu and Indian express
and 35
read ONLY times of India and Indian express)
75 degrees
30h – 11/2 m = 240 – 165 = 75 ..
tan 30=h/x
tan 15=h/100+x
so h/tan 30=(h/tan 15)-100
=33.33app
Assume his salary was Rs. X
He earns 5% raise. So his salary is (105*X)/100
A year later he receives 2.5% cut.
So his salary is ((105*X)/100)*(97.5/100)
which is Rs. 22702.68
So Ans is Rs.22176