Ques:- Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?
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Ques:- If a car starts from A towards B with some velocity due to some problem in the engine after travelling 30km.If the car goes with 4/5 th of its actuval velocity the car reaches B 45min later to the actual time. If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual time , what is the initial velocity of car and what is the distance between A and B in km
Recent Answer :
: Ans. let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=> 4x-12y=120 —-(1).
45/y + (x-45)5/4y -x/y=3/5
=> 5x-12y=225 ——-(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25 km/hr
and Distance From A to B is 105 km
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A. 6
B. 8
C. 10
D. 12
E. 14
Recent Answer :
: 6
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Recent Answer :
: cant say
If c is 5 times faster than a then he can do it in 2 days alone.
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Ques:- Some toys were distributed equally among 18 children in such a way that the number of toys each child gets is equal to the total number of children and after distribution 6 toys are left out. What was the total number of toys?
A. 324
B. 330
C. 336
D. 320
E. None of these
Recent Answer :
: (b) 330 is the amswer
as the no of toys are equall to no of students
18*18= 324
left out toys afetr distribution = 6
so 324+6= 330
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Recent Answer :
: 3 minutes
₹1 today increases to (1+1/8) = 9/8 after 1year.
After 2 years it increases to 9/8 of 9/8 = (9/8)^2 =81/64 times.
Hence ₹64000 increase to 64000×81/64 =₹81000