Ques:- Let S be the set of prime numbers greater than or equal to 2 and less than 100. Multiply all the elements of S. With how many consecutive zeros will the product end?
A. 1
B. 4
C. 5
D. 10
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Recent Answer :
: Hog
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Ques:- 8400 ? 120 x 15 + 150 = ?
Recent Answer :
: 8400 ? 120 x 15 + 150 = ?
ans:
8400 % 120 x 15 + 150 = ?
1200
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Ques:- In what time will a train 100 m long cross an electric pole, it its speed be 144 km/hr?
Recent Answer :
: 2.5 sec
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Ques:- In 1991, was the number of people in City A three times greater then the number of people in City B?
Recent Answer :
: question is incomplete
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Ques:- A train takes 9 sec to cross a pole. If the speed of the train is 48 kmph, then length of the train is
A. 80 m
B. 90 m
C. 120 m
D. 150 m
Recent Answer :
: DISTANCE=TIME *SPEED
D=?
48*(5/18)=13.33m/s
D=9*13.333=120m
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A. Pepe of London
B. Wrangler
C. Numero Uno
D. Lee
Ques:- What is your hobbies
Ques:- Find out the wrong number in the series:
4, 9, 16, 25, 32, 49
4, 9, 16, 25, 32, 49
A. 16
B. 25
C. 32
D. 49
Recent Answer :
: Please explain to me why the answer is C. Thank you
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Recent Answer :
: white
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Ques:- Manisha ranked sixteenth from the top and twenty ninth from the bottom among those who passed an examination. Six boys did not participate in the competition and five failed in it. How many boys were there in the class ?
Recent Answer :
: Total 55
Manisha is a girl name so 54 boys
1 girl
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Ques:- Find the least number which when divided by 35 leaves remainder 25, when divided by 25 leaves remainder 15 and when divided by 15 leaves remainder 5?
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Ques:- What will be the value of 25 mps in kmph?
Recent Answer :
: 10000
To determine how many consecutive zeros the product of S will end with, we need to find the highest power of 10 that divides the product. This is equivalent to finding the highest power of 5 that divides the product, since the number of factors of 2 will always be greater than the number of factors of 5.
The primes in S are {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}.
There are 24 primes in S, so the product of S is:
2 x 3 x 5 x 7 x 11 x 13 x 17 x 19 x 23 x 29 x 31 x 37 x 41 x 43 x 47 x 53 x 59 x 61 x 67 x 71 x 73 x 79 x 83 x 89 x 97
We need to find the highest power of 5 that divides this product. To do this, we count the number of factors of 5 in the prime factorization of each number in S.
5 appears once: 5
5 appears once: 25
5 appears once: 35
5 appears once: 55
5 appears once: 65
5 appears once: 85
So, there are six factors of 5 in the product of S. However, we also need to consider the powers of 5 that arise from the factors 25, 35, 55, and 65.
25 = 5 x 5 appears once: 25
35 = 5 x 7 appears once: 35
55 = 5 x 11 appears once: 55
65 = 5 x 13 appears once: 65
Each of these numbers contributes an additional factor of 5 to the product of S. Therefore, there are 6 + 4 = 10 factors of 5 in the product of S.
Since each factor of 5 corresponds to a factor of 10, we know that the product of S will end with 10 zeros. Therefore, the product of S will end with 10 consecutive zeros