Ques:- Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is -.
Recent Answer : Added by Admin On 2022-09-28 18:05:55:
Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1 cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2 i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61,P(B)=61,P(C)=65,P(A)=61,P(B)=65,P(C)=61 and P(A)=65,P(B)=61,P(C)=61
Hence the required probability = 61×61×65×6×3=21690=125
Ques:- Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:20:
Answer: 50 kmph.
Explanation:
Let the distances between city A to B and B to C be 2x km and 3x km respectively.
Total time taken to cover from A to C
= (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.
Ques:- There is a safe with a 5 digit No. The 4th digit is 4 greater thansecond digit, while 3rd digit is 3 less than 2nd digit. The 1st digit is thrice the last digit. There are 3 pairs whose sum is 11. Find the number
Ques:- There are 2 toy cars facing each other at a distance of 500 cm from each other. Then they moves forward by 100 cm at a speed of 50 cm/s and then moves backward by 50 cm at a speed of 25 cm/s. Evaluate the time of their collision.
Recent Answer : Added by Meriam Saad On 2022-03-09 16:36:15:
9s
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Ques:- How many times in a day, the hands of a clock are straight?
A. 22
B. 24
C. 44
D. 48
Recent Answer : Added by Sanjana Balasaheb Deore On 2022-03-09 16:26:16:
22
Ques:- In each questions below are given two statements followed by two conclusions numbered I and II. Statements : All pens are roads. All roads are houses. Conclusions :
I. All houses are pens.
II. Some houses are pens.
A. if only conclusion I follows
B. if only conclusion II follows
C. if either conclusion I or II follows
D. if neither conclusion I nor II follows
E. if both conclusions I and II follow
Recent Answer : Added by Ritu Verma On 2021-12-20 03:54:58:
A.
Ques:- In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?
Recent Answer : Added by Mogomotsi On 2021-11-24 16:45:04:
2a; 2a+2; 2a+4; 2a+6; 2a+8; 2a+10
t_2 + t_6 = 24 => 2a+2 + 2a + 10 = 24 => a = 3
therefore t_4 = 2(3) + 6 = 12
Ques:- A boy travels in a scooter. After covering 2/3rd of the distance, the wheel got punctured. He covered the remaining distance by walking. Walking time is twice of the time taken in scooter. How many times the riding speed is of the walking speed?…
Ques:- Which one of the following is a prime number?
A. 143
B. 221
C. 343
D. 823
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Ques:- If 3 workers collect 48 kg of cotton in 4 days, how many kg of cotton will 9 workers collect in 2 days?
Recent Answer : Added by Yadu Krishnan S On 2022-08-14 16:42:43:
72
Ques:- The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten's place of the originalnumber is equal to twice the difference between its digits. What is the number?
Ques:- x==2+2^(2/3)+2^(1/3) .Then what is the value of x^3-6X^2+x ? here X^Y indicates X to the power of Y.
Recent Answer : Added by Admin On 2020-05-17 12:04:34:
Recent Answer : Added by Sudeshna Roy On 2022-08-24 17:03:04:
Prosperity for all
Ques:- Raj has a jewel chest containing Rings, Pins and Ear-rings. The chest contains 26 pieces. Raj has 2 and 1/2 times as many rings as pins, and the number of pairs of earrings is 4 less than the number of rings. How many earrings does Raj have?…
Recent Answer : Added by King11 On 2022-03-18 09:20:21:
6 pairs of earrings. So 12 earrings.
The total has to be 26, so let’s say there’s 6 pairs of earrings and the number of pairs has to be 4 less than the number of rings. So that would make 10 rings. The 10 rings has to be 2 1/2 greater than the number of pins. So you would divide 10/2.5 = 4 Pins. That would equate to a total of 12 earrings, 10 rings, and 4 pins. A total of 26 pieces.
Ques:- ABCDE are sisters. Each of them gives 4 gifts and each receives 4 gifts No two sisters give the same combination ( e.g. if A gives 4 gifts to B then no other sisters can give four to other one.)
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Ques:- Find the odd man out:
41, 43, 47, 53, 61, 71, 73, 81
A. 81
B. 73
C. 71
D. 61
Recent Answer : Added by Makeshkumar.M On 2022-08-14 16:46:39:
81
Ques:- A man leaves office daily at 7pm A driver with car comes from his home to pick him from office and bring back homeOne day he gets free at 5:30 and instead of waiting for driver he starts walking towards home. In the way he meets the car and returns home on car He reaches home 20 minutes earlier than usual.In how much time does the man reach home usually??
Recent Answer : Added by Admin On 2022-09-29 16:32:20:
Answer:
Since the car has met the person 20 minutes before hand, it has actually saved 10 mins of journey (to and fro)
since the man has started 1.30 hrs before and car has met him 10 mins before actual time he takes to reach daily is 1hr and 20 mins
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Ques:- A hare and a tortoise have a race along a circle of 100 yards diameter. The tortoise goes in one directionand the hare in the other. The hare starts after the tortoise has covered 1/5 of its distance and that too leisurely.The hare and tortoise meet when the hare has covered only 1/8 of the distance. By what factor should the hareincrease its speed so as to tie the race?
Recent Answer : Added by DK BOSS On 2021-07-30 16:27:01:
Let A, B and C be the three 6-faced dice.
Then, according to the question,
Since two dices has to be equal, that value can be any of the 6 faces, i.e., 6C1 cases.
Now for each case, 2 equal dices can be selected from 3 dices in 3C2 i.e., 3 ways.
And for each of the above, the third dice can have any of the 5 remaining faces
The possible outcomes are P(A)=61,P(B)=61,P(C)=65,P(A)=61,P(B)=65,P(C)=61 and P(A)=65,P(B)=61,P(C)=61
Hence the required probability = 61×61×65×6×3=21690=125