Ques:- A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. What is the speed of the train ?
Recent Answer : Added by Swaleh Mohamed On 2022-08-14 16:45:53:
Length of train = 125Mtrs
Speed of man = 5Km/Hr
=(5*1000)/(1*3600)
=1.4M/s
Time taken for train to pass = 10s
Spd = D/T
Total Distance (Man distance+ Train Length)
#Distance covered by Man in 10s
D=Spd*T
= (1.4M/s*10s)
= 14Mtrs
#Train length = 125Mtrs
Total D = 14Mtrs + 125Mtrs
= 139Mtrs
Time taken = 10s
Sp = D/t
=139M/10s
=13.9M/s
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Ques:- 1,2,3,5,?,10,15,30
Recent Answer : Added by Admin On 2020-05-17 12:04:34:
these r all factors of 30
1*30=30
2*15=30
3*10=30
5*6=30
like that
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2.88
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Recent Answer : Added by Emily Tilden On 2022-08-14 16:43:10:
Bopri is farthest to the west followed by Kakran, Akram, Tokhada, and Paranda to the east.
Ques:- A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Recent Answer : Added by George On 2021-06-10 07:10:11:
total distance to travel the end of the train = 360 + 140 = 500 m
speed of train 45000m/60min = 750m/min or 750m/60sec
(500m*60sec)/750m=40sec the time will take to pass
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Recent Answer : Added by Admin On 2020-05-17 12:01:13:
By 1hour both trains meet, so the distance travel by fly in
1hr is 120km.
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20
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Ques:- Find out the distinct numbers that can be formed by 2, 3, 7, 6(don?t now exactly) that should be divided by 4?
Recent Answer : Added by Abdul On 2022-05-17 09:06:31:
Ans = 8
Use simple box method
[1][2][2][2]= 1x2x2x2 =8
Logic >
once place have 2 number (2,6)
Tens place have also 2 number (7,3)
So that number is divisible by 4
Now, 2 numbers fixed at once and tens place left 2 numbers which is choice at hundredth place
Now 3 number fix left 1 number which is placed at thousands place
Total number form is 4×4 = 16
But divisible by 4 is 1x2x2x2 =8
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Recent Answer : Added by Admin On 2020-05-17 12:00:30:
Fuel to go = x + (x/4)=5x/4
Fuel to come = x
now,
x+(5x/4) = 4.5
9x/4 = 4.5
9x = 18
x = 2 (Fuel to comeup)
Fuel to go will be:
2+(2/4) = 2 + (0.5) = 2.5
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Length of train = 125Mtrs
Speed of man = 5Km/Hr
=(5*1000)/(1*3600)
=1.4M/s
Time taken for train to pass = 10s
Spd = D/T
Total Distance (Man distance+ Train Length)
#Distance covered by Man in 10s
D=Spd*T
= (1.4M/s*10s)
= 14Mtrs
#Train length = 125Mtrs
Total D = 14Mtrs + 125Mtrs
= 139Mtrs
Time taken = 10s
Sp = D/t
=139M/10s
=13.9M/s