es, of course, there are a lot of people who start their careers with small things but after a few years, they grow themselves and get into better places. All you have to do is learn the skills of your desired domain while working on the other part and then use that to get a job in your desired place.
For example, consider you are an engineer and worked in a firm where you worked as a sales executive but you want to work as an IT professional in any IT firm then while working as a sales executive you can try to learn some coding languages like C or Java and after getting a good command on that you can apply for a job of developer or any IT professional. The only disadvantage is that your sales experience will have nothing to contribute to your IT job so you’ll be hired and paid as a fresher only.
I hope this helps you.
Product of two numbers = 1320
HCF = 6
LCM = x
Formula:
Product of two numbers =(HCF *LCM)
1320=(6*x)
x=1320/6
x=220
LCM Of the numbers is220
The answer for this question is very simple: it is called Ceaser Cipher.
It consists of replacing a character by another located in (current character position + (key-1)), where key = how many positions you want to skip.
For Example: VICTORY -> YLFWRUB with the key = 3.
Then SUCCESS -> QXFFHQQ
Note: it should work like a circle(Z+1 = A).
If Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.
V – x = A + x — (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.
390
12
3 days
4
Triangular Prism
A Roman was born the first day of the 35th year before Christ means before the start of year 0, 35 years has been past and died the first day of the 35th year after Christ means 35th year is about to start at his death so only 34 years has been completed so total years = 69
Total number of pairs is NC2^{N}C_2NC2. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2 – N = 28/2 = 14. If N = 7,
7C2 – 7 = 21 – 7 = 14….
N =7
sister
A