Faculty of veterinary medicine university of zagreb Interview Questions, Process, and Tips

b

Servlets are faster as compared to JSP, as they have a short response time.
JSP is slower than Servlets – JSP is a HTML-based codes.
Servlets are harder to code, as here, the HTML codes are written in Java – JSPs are easier to code, as here Java is coded in HTML.
In an MVC architecture, Servlets act as the controllers. – In MVC architectures, the JSPs act as a view to present the output to the users.
The service() function can be overridden in Servlets. – The service() function cannot be overridden in JSPs.

They will meet at the center of the square…as the
direction vector of all the ants/people change according to
the first person.
The independent path of each person taken will be spiral in
nature.

28th February,1956

C

240.

X : (3000 x 8) + (2000 x 4) = 32000
Y : (4000 x 8) + (5000 x 4) = 52000
X:Y = 32000:52000 = 8:13
8k + 13k = 630
k = 30
X:8 x 30 = 240

The answer is A)

y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg

y2 – y1 = 10 Rs/kg

The distance between the y and y1 is

y – y1 = 64.5 – 62 = 2.5

x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75

The target price is calculated by the lever method.

x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5

The ratio is of y1 to y2 is

0.75 : 0.25

Divide by both by 0.25

3 : 1

6*6=36 medals
6 days

1st day=1+35/7=6 remaining 30 medals
2nd day=2+28/7=6 remaining 24 medals
3rd day=3+21/7=6 remaining 18 medals
…
6th day 6 medals

5/9

u c 5 numbers…..
we add the combination of digits…..
a.17->1+7=8(even)
b.23->2+3=5(odd)!!!!!
c.37->3+7=10(even)
d.13->1+3=4(even)
e.73->7+3=10(even)
all combinations are even xept 23
ans:23

the answer is E

For optimal size of a project team..
the % increase in staff size should be “Zero”
reason:
additional member directly proportional to increase in
staff size..

c

C

127.179(app)
given distance of the train along the wind is 695
and againt the wind is 498
and time = distance/speed
as we know that time is equal in both the cases hence equate
695/s1=498/s2———–(1);
where s1=speed of the plane + speed of the wind
and s2=speed of the plane -speed of the wind
given that speed of the wind is 21k/h
s1=sp+21
s2=sp-21
substitu in eq 1
we get the answer as 27.17(app)