Dovetail games Interview Questions, Process, and Tips

let the total work to be done =1
so a+b+c=1 (say)
then a and b are supposed to do 7/11 th of work
so c= 1- (7/11)
c=4/11
therefore c gets (4/11)*550
=200 is the answer

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

The first number is 36

Step-by-step explanation:
let their common factor be ‘x’

hence,

the ratio be 3x/5x

hence, by condition;

(3x-9)/(5x-9)=9/17 ch upu

9(5x-9)=17(3x-9)

45x-81=51x-153

153-81=51x-45x

72=6x

x=72/6

x=12

the first number is 3x=3×12=36

Pen can’t be sharpened by sharpener
Pencil is only sharpened by sharpner
Likewise rigth man can only fill the rigth position so we have to select it. This is human resource recruiting.
In school teachers manage and motivate you to do your work.
The same is done to employees this is hrms

C)3

56

Perimeter of semi circular = πr+2r

Where r is radius , π = 22/7

πr+2r= 144 (given)

(22/7)r +2r = 144

22r+14r = 144*7 (multiply both sides by 7)

36r = 144*7

r= 144*7/36 = 28

radius =28 cm

Area =( 1/2)πr^2

Area=( 1/2 )*(22/7)*28*28

= 1232cm^2
Ans : area is 1232 cm^2

Let’s say, length of train = x metres
Speed at pole = Speed at platform
x/15 = 100+x / 25
5x = 300 + 3x
2x = 300
x = 150m
So, train is 150 metres long.

Avg = 2(X*Y)/X+Y
2*(60*40)/60+40
2*(2400)/100
2*24
48.

2nd

Friends,
The Answer given by ‘Gaurav Sharma’ is correct and
the approach (bottom to top) suggested by ‘Shailesh’ is
good. But with minor correction we can arrive the solution
using this approach:
After 5th loot, No. of breads left = 3
after 4th loot, no. of breads left = (3+0.5)x2 = 7
after 3rd loot, no. of breads left = (7+0.5)x2 = 15
after 2nd loot, no. of breads left = (15+0.5)x2 = 31
after 1st loot, no. of breads left = (31+0.5)x2 = 63
So, before 1st loot, no. of breads left = (63+0.5)x2 = 127

=> 3s = d
=> 5(s-9) = d

therefore
5s-45=3s
2s = 45
s=22.5

hence
d= 67.5

let x be sum.
SI of 18% for 1 year= x*18/100=0.18x;
SI of 18% for 2 years is 0.36x;

SI of 12% for 1 year= x*12/100=0.12x;
SI of 12% for 2 years is 0.24x;

Given, 0.36x-0.24x=840
0.12x=840
x=840/0.12=7000.

area is doubled.
actual area = 1/2 bh
after increase area = 1/2 *4b* h /2
=bh
1/2 *bh *2 = bh
therefore area is doubled

list price – actual price markrd by the company
net price (average price of all items inclusive all discounts,breakage & so on.) which is 425 i.e. 50% of the marked price
hence the list price or marked price is twice the net sale price = 850
50%=425
100%=?
=100%*425/50=850

In the example first we have to find the area of the field

we have given the following values ,

cost of fencing per meter = Rs 1.50

Diameter of circular field = 28

We have to find the area , a = ?

We know that,

Area = 2 π r

= 2 x 22/7 x 14

= 2 x 22 x 2

= 44 x 2

= 88 sq. m

So, area of circle is 88 sq.m

Now just multiply it with 1.50

cost of fencing = 88 x 1.50

= Rs. 132

So, the cost of fencing the circular field is Rs. 132