Ques:- Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 16 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?
Recent Answer : Added by Rudradeb Biswas On 2021-08-16 05:26:57:
444km
Since the speed diff is 5km/h
It takes 12 hrs to cover 60 extra kms
Therefore in 12 hrs the total dist covered is
Relative speed×time=(21+16)×12=444 kms
Ques:- A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40, what is reduced price per dozen?
Recent Answer : Added by Pavithra On 2023-05-26 01:10:38:
Reduction of 40% or 4/10th in price of bananas will lead to an increase of 4/(10 – 4) = 2/3rd part in quantity if expenditure is constant.
If original quantity is q, then :
2q/3 = 64
=> q = 64 x 3/2 = 96 = 8 dozens.
=> Original price per dozen = 40/8 = Rs 5
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Recent Answer : Added by Admin On 2020-05-17 11:59:58:
s1(1+x/100)+s2(1+x/100)+s3(1+x/100)
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Ques:- A dishonest shopkeeper professes to sell pulses at the cost price, but he uses a false weight of 950gm. for a kg. His gain is____%.
Recent Answer : Added by Rohit Saha On 2021-09-16 17:27:37:
let’s say the Cost Price is 1000x. (CP)
The selling price is also the same as the Cost price. So, here SP=CP (But he sells 950gm instead of 1000gm)
Instead of 1000gm, he is selling 950 grams at the CP. So he sells 050 gms @1000x price. So his net profit is 50gm.
Now 1000gm is 1000x Rs
So, 50gms is 50x rs. [Apllied Unitary Method]
So his profit percentage is:
Profit Percentage Formula: {(Profit/CP)*100%}
So, Here profit is 50x;
CP is 1000x;
so putting the value in the formula we get, Profit Percentage is: (50x/1000x)*100% =(5000x/1000x)%=5%.
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Recent Answer : Added by Nishara Pathirana On 2023-04-18 07:32:50:
Assume Q can do the work alone in Q days:
work of a day by both P and Q =>
(1/15) + (1/Q ) = 1/6
solving this Q = 10.
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Recent Answer : Added by shubham On 2021-10-07 15:41:19:
192 zeros in 1 to 1000
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Recent Answer : Added by MAMIDI LIJITA SREE On 2023-01-21 17:36:29:
1
Ques:- A is driving on a highway when the police fines him for over speeding and exceeding the limit by 10 km/hr. At the same time B is fined for over speeding by twice the amount by which A exceeded the limit. If he was driving at 35 km/hr what is the speed limit for the road?
Recent Answer : Added by Eyang, Daniel Eyoh On 2022-08-24 17:03:24:
15km/hr
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Recent Answer : Added by priyanhu On 2022-04-02 07:00:15:
Thanq saddha
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Recent Answer : Added by shravan kumar saraf On 2022-08-24 17:03:03:
144
Ques:- If a car starts from A towards B with some velocity due to some problem in the engine after travelling 30km.If the car goes with 4/5 th of its actuval velocity the car reaches B 45min later to the actual time. If the car engine fails ofter travelling 45km, the car reaches the destination B 36min late to the actual time , what is the initial velocity of car and what is the distance between A and B in km
Recent Answer : Added by DK BOSS On 2021-07-17 06:18:31:
Ans. let x is distance from A to B
and y is initial speed.
30/y+(x-30)5/4y -x/y = 3/4
=> 4x-12y=120 —-(1).
45/y + (x-45)5/4y -x/y=3/5
=> 5x-12y=225 ——-(2).
From equ (1) and equ (2) we will get.
x=25 and y=105
so initial speed is 25 km/hr
and Distance From A to B is 105 km
444km
Since the speed diff is 5km/h
It takes 12 hrs to cover 60 extra kms
Therefore in 12 hrs the total dist covered is
Relative speed×time=(21+16)×12=444 kms