Chitkara university Interview Questions, Process, and Tips

1600 years contain 0 odd day.
300 years contain 1 odd day.
94 years = (23 leap years + 71 ordinary years)
= (46 + 71) odd days
= 117 odd days, i.e., 5 odd days
Days from 1st January 1995 to 28th February 1995
= (31 + 28) days = 59 days
= (8 weeks + 3 days) = 3 odd days
∴ Total number of odd days
= (0 + 1 + 5 + 3) = 9 odd days i.e., 2 odd days.
So, the required day is Tuesday.

the capital of India is New Delhi
the capital of Pakistan is Islamabad
the ans is(b)Islamabad

Ratio: 3/4

= (1 * 5! * 2!) * 3 + ( 2! * 5 ! * 1) * 3 + ( 3! * 5! ) + ( 5! * 3! )

100

1) time =20mins,speed=15kmph=15*(5/18)=25/6 m/sec
distance=20*(25/6)=250/3 m
then 2) given as time =15min
speed=250/3*15=(50/9)*(18/5)kmph=20kmph

12

94

14 km/h

2.01%

mausi

G.c.d=num1 *num2/lcm
Num1=20
Gcd=5
Lcm=60
5=(20*num2)/60
Num2= 5*60/20
Num2=15

A wet stone

2:3:4

8/15 left.

1/15 * 4 + 1/20 * 4 = 7/15
1 – 7/15 = 8/15

Answer:
11 days.

Step-by-step explanation:
In the question,

Time taken by Ramesh to finish a piece of work = 20 days

Time taken by Sushil to finish a work = 25 days

Time for which they worked together = 5 days

Sushil left after = 5 days

So,

One day work of Ramesh is,

One day work of Sushil is,

So,

Work done in 5 days is given by,

Therefore, Remaining work is given by,

Now, as the Sushil left the remaining work was done by Ramesh,

Time taken by Ramesh for the remaining work is,

Therefore, the remaining work will be completed in 11 days by Ramesh.

5 (3+2)
if he wins then it becomes 4 double than 2
and if looses then opponent becomes 3 which is equal.