Anaplan Interview Questions, Process, and Tips

Error is at 48. Correct once is 58

9 and 16

C. 4

In the example first we have to find the area of the field

we have given the following values ,

cost of fencing per meter = Rs 1.50

Diameter of circular field = 28

We have to find the area , a = ?

We know that,

Area = 2 π r

= 2 x 22/7 x 14

= 2 x 22 x 2

= 44 x 2

= 88 sq. m

So, area of circle is 88 sq.m

Now just multiply it with 1.50

cost of fencing = 88 x 1.50

= Rs. 132

So, the cost of fencing the circular field is Rs. 132

I’m interested in this job because I can see that, in this role, my skills could help solve this problem within your company. I also see an opportunity for me to learn and grow these skills, so we both would benefit personally, professionally, and financially.

TEACHER is written as VGCEJGT, how would DULLARD ?
T value is 19
V value is 21 ,
here we get to know that there is difference of 1 letter between them.
Answer: FWNNCTF.

562.

white

4) QEOKTWG

CITOXE

211

The most important belief is belief in yourself. Believing in who you are and your abilities frees you to pursue goals and dreams without reservation and drives you forward with confidence, independence, autonomy and direction. Combine this conviction in yourself with a solid framework of inherent beliefs from the list above, and you have an unbeatable combination.

20 minutes

Mother

let the total work to be done =1
so a+b+c=1 (say)
then a and b are supposed to do 7/11 th of work
so c= 1- (7/11)
c=4/11
therefore c gets (4/11)*550
=200 is the answer

Balls- B1, B2, B3, B4, B5, B6, B7, B8, B9.
Group1 – (B1, B2, B3), Group2 – (B4, B5, B6), Group3 – (B7, B8, B9)
Now weigh any two groups. Group1 on left side of the scale and Group2 on the right side.
When weighing scale tilts left – Group1 has a heavy ball or right – Group2 has a heavy ball or balanced – Group3 has a heavy ball.
Lets assume Group 1 has a heavy ball.
Now weigh any two balls from Group1. B1 on left side of the scale and B2 on right side.
When weighing scale tilts left – B1 is the heavy or tilts right – B2 is the heavy or balanced – B3 is the heavy.

= (1 * 5! * 2!) * 3 + ( 2! * 5 ! * 1) * 3 + ( 3! * 5! ) + ( 5! * 3! )

Product of two numbers = 1320
HCF = 6
LCM = x
Formula:
Product of two numbers =(HCF *LCM)
1320=(6*x)
x=1320/6
x=220
LCM Of the numbers is220

Use 3pt. Formula
( (x-x1)/(x2-x1) )=( (y-y1)/(y2-y1) )
We get 150