Ques:- It was calculated that 75 men could complete a piece of work in 20 days. When work was scheduled to commence, it was found necessary to send 25 men to another project. How much longer will it take to complete the work?
Recent Answer : Added by Admin On 2022-09-29 15:28:07:
One day work = 1 / 20
One mans one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 =
30
Ques:- What skills does a leader need to have? why?list the steps you would take in building up a team? how about a team with low morale?what do you do to prioritized on a given workday?
Ques:- List out the difference between the largest number and the least number written with the figures 3, 4, 7, 0, 3?
Ques:- How much interest can a person get on Rs. 8200 at 17.5% p.a. simple interest for a period of two years and six months?
Ques:- A and B can do a work in 12 days, B and C in 30 days and C and A in 36 days. In how many days will the work be completed, if all three of them work together?
Ques:- Grass in lawn grows equally thick and in a uniform rate. It takes 24 days for 70 cows and 60 days for 30 cows to eat the whole of the grass. How many cows are needed to eat the grass in 96 days?
Recent Answer : Added by Admin On 2020-05-17 12:01:01:
Use 3pt. Formula
( (x-x1)/(x2-x1) )=( (y-y1)/(y2-y1) )
We get 150
Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Recent Answer : Added by Admin On 2020-05-17 12:01:55:
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.
Ques:- When 2 is added to half of one-third of one-fifth of a number, the result is one-fifteenth of the number. Find the number?
Ques:- Every day a cyclist meets a train at a particular crossing .The road is straight before the crossing and both are travelling in the same direction.Cyclist travels with a speed of 10 kmph.One day the cyclist come late by 25 minutes and meets the train 5 km before the crossing.What is the speed of the train?
Ques:- Information regarding family members
Ques:- Lethargic : Vital :: Trite : ?
A. Unique
B. Slug
C. Lazy
D. Skinny
Recent Answer : Added by keerthi On 2021-07-22 15:55:54:
A
Ques:- In one sentence, describe your experience at this company?
Ques:- How is my mother’s mother’s only son-in-law’s sister related to me ?
Recent Answer : Added by Atif On 2022-12-05 16:13:29:
Father’s sister
Ques:- If the HCF of two numbers is 2 and their LCM is 70, then the numbers are
A. 2, 35
B. 4, 70
C. 6, 70
D. 14, 10
Recent Answer : Added by Cynthia Birungi Muhumuza On 2022-08-14 16:34:42:
d
HCF= 2
LCM = 2*5*7 = 70
Ques:- Why only manufacturing? why not sales, marketing,quality etc.?
Ques:- Educational Qualifications,work experience,Achievements done with pat companies worked with.
Ques:- Sir, My educational details: xth in 1992 with 75.4% inter in 1994 with 53.4% B.Tech.,in 2004 with 65.5%and also having certifications like MCP & MCSAI am going to apply for the post.You satisfied with your academic results?
Ques:- What is the power of 2?optionsa.2068b.2048c.2668please explain the concept behind this.It can be asked interms of power 3,4 etc.
Ques:- Basics of our subjects in cse dept
Ques:- A report has 20 sheets each of 55 lines and each line consists of 65 characters. If this report is to be retyped with each sheet having 65 lines and each line of 75 characters wht will be the reduction percent in the pages ?
A. 22.5 %
B. 35
C. 25
D. none
Recent Answer : Added by Admin On 2020-05-17 12:05:39:
Ques:- 361 -> 22121 -> 1481 -> 1225 -> XWhat is the value of X?
Ques:- Asked about me my qualification and typing speed
Ques:- Tell me your three good qualities?
Ques:- 343 : 729 :: 125 : __
Recent Answer : Added by Sunil Kumar On 2022-08-14 16:25:38:
343 : 729 :: 125 : ?
7^3 : 9^3 :: 5^3:7^3
Ques:- What things give you greatest satisfaction?
Ques:- Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?
Recent Answer : Added by Akhilendra pratap Singh On 2022-09-23 18:02:22:
Marks in thrice in english as in science
so if science marks is x
then english marks = 3x
lets maths marks = y
ratio of english and maths marks is
3x/y = 3/5
=> y = 5x
and total marks = 162
3x + x + 5x = 162
x = 18 —-answer
Ques:- How to answer freshers “tell me about your self?”
Ques:- A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long?
Recent Answer : Added by dumeel kuppam vavvaalu On 2021-08-25 14:15:33:
From the first statement
Speed=distance/time
=>240/24=10m/s
so speed=10m/s
From the second statement
distance=length of the platform+length of the train=650+240=890m
Time=distance/speed
here, the speed of the train is already calculated
=>890/10=89s
So the time taken by the train to cross the platform is 89 seconds
Ques:- How many companies from India found place in ?Global-500? list ?
One day work = 1 / 20
One mans one day work = 1 / ( 20 * 75)
Now:
No. Of workers = 50
One day work = 50 * 1 / ( 20 * 75)
The total no. of days required to complete the work = (75 * 20) / 50 =
30