Ques:- The H.C.F and L.C.M of two numbers are 44 and 264 respectively. If the first number is divided by 2, the quotient is 44. The other number is
A. 66
B. 132
C. 264
D. 528
Recent Answer : Added by Shiva Akhil On 2023-06-09 12:28:38:
let,first num be x and second num be y
hcf =264
lcm=44
given equation
x/2=44 i.e x=88
product of 2 numbers is equal to lcm*hcf
88*y=44*264
y=132
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Recent Answer : Added by Durai On 2023-05-11 12:54:20:
4 years
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Recent Answer : Added by Aditya Jadhav On 2021-12-04 15:03:07:
R
T,P,R,Q,S
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Ques:- A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Recent Answer : Added by Admin On 2022-09-29 19:29:04:
Speed = (45×518)m/sec=252m/sec
Total distance covered = (360+140) m = 500 m.
∴Required time= 500×225sec = 40 sec.
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Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
Recent Answer : Added by Ben Gulliano On 2023-05-23 15:53:20:
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds
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A. a multiple of 3
B. a multiple of 5
C. zero or a multiple of 7
D. zero or a multiple of 11
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Recent Answer : Added by Nitesh On 2021-05-28 08:49:20:
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Ques:- The prime numbers dividing 143 and leaving a remainder of 3 in each case are
A. 2 and 11
B. 3 and 7
C. 5 and 7
D. 11 and 13
Recent Answer : Added by Mbabazi Nuriat On 2022-05-17 08:55:04:
let,first num be x and second num be y
hcf =264
lcm=44
given equation
x/2=44 i.e x=88
product of 2 numbers is equal to lcm*hcf
88*y=44*264
y=132