Universal Transaction Processing Interview Questions, Process, and Tips

When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.

Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.

So, in a race of 1000 meters, A beats C by (1000 – 787.5) = 212.5 meters to C.

So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.

1/5

Average = (1+2+3+4+5+6+7+8+9)/3
= 45/3 = 15
Every side will contain sum of 15.
1st side contains 8 and 7.
2nd side contains 9 and 6.
3rd side contains 1,2,3,4 and 5.

1(100-1)+ 2(100-2)+…..99(100-99)
N=100
solution: N(N-1)
100(99)= 9900

Ans- 6,6 litres
Let x Litres from can1 (where, water = x/4 litres and milk = 3x/4 litres)
Now
12-x liters from can 2 ( where, water = 6-x/2, milk = 6-x/2)

Now given
water/milk = 3/5
0.25x+6-0.5x / 0.75 +6-0.5x = 3/5
6-0.25x/6+0.25 = 3/5
Solve it you get
x = 6 litres from can1
Then 12-x= 12-6=6 litres from can2

Reliance

If Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.
V – x = A + x — (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.

5
307,311,313,317,319

30,40

10*(root 2)

Solution:

As given, we have,

The cost of one pen = 36 Rs.

So, the cost of 15 pens = 36 × 15 = 540 Rs.

The cost of one book = 45 Rs.

So, the cost of 12 books = 45 × 12 = 540 Rs.

The cost of one pencil = 8 Rs.

So, the cost of 10 pencils = 8 × 10 = 80 Rs.

Now,

the cost of each eraser is 40 Rs. less than the combined costs of pen and pencil.

So,

Combined costs of pen and pencil = 36 + 8 = 44 Rs.

Cost of one eraser = 44 – 40 = 4 Rs.

So, the cost of 5 erasers = 4 × 5 = 20 Rs.

Hence,

The total amount spent is

Hence, the total amount spent is 1180 Rs.

I belive it is 3:45 hrmins

B