120
time = distance / speed
speed = 36*(5/18) m/s=10m/s
distance = 100m
time=100/10s = 10sec
a
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
1/4E(E decreses by 4 times)
125
This is a sequence of English letters, in numbers.
⇒ ten = 3 letters
⇒ nine = 4 letters
⇒ sixty = 5 letters
⇒ ninety = 6 letters
⇒ seventy = 7 letters
⇒ Sixty six =8 letters
⭕️This logical question goes with the no. of letters in the number!!!!!!!
⭕️∴ the biggest number with 9 letters will be ninety-six (96).
2*3*5*7*11*13*17*19=9699690
Answer :sister- in- law
explanation: y is the daughter of x’s brothers wife’s father-in-law = y is the daughter of x’s brother’s wife’s father = y is the wife of x’s brother = y is x’s sister-in-law
Let the number of one rupee coins in the bag be x.
Number of 50 paise coins in the bag is 93 – x.
Total value of coins
[100x + 50(93 – x)]paise = 5600 paise
=> x = 74
ANS = 74
10000
one-legged =5% of 10000=500
remaining=10000-500=9500
barefooted=9500/2=4750
remaining people= 9500-4750=4750
hence required number of shoes= 4750*2+500*1=100005% of 10000 = 500 one legged
9500 / 2 = 4750 bare foot
minium no of shoes = 4750*2 + 500*1 = 10000
( a ) BQDCJCMF
“TERMINAL” split it into the half we get “TERM” “INAL”
Now the first half is decreased by one and the next half is
increased by one, so we get:
“SDQLJOBM” (pls note in the ques we have “SDQIJOBM” where
‘L’ shud have come instead of ‘I’)
so “CREDIBLE” is to “BQDCJCMF”
I believe it will be 30 km/hr