STIC SOFT E-SOLUTIONS is a dynamic technology company that specializes in providing innovative digital solutions tailored to meet the diverse needs of its clients. Renowned for its expertise in software development, IT consulting, and digital transformation services, STIC SOFT E-SOLUTIONS has established itself as a trusted partner for businesses seeking to leverage technology for competitive advantage.
With a focus on delivering excellence and value, STIC SOFT E-SOLUTIONS offers a comprehensive suite of services designed to empower organizations across various industries. From developing cutting-edge software applications to implementing robust cybersecurity measures, the company's solutions are crafted with precision and backed by industry best practices.
At the heart of STIC SOFT E-SOLUTIONS is a team of highly skilled professionals who are passionate about harnessing the power of technology to drive positive change. With a customer-centric approach, the company works closely with clients to understand their unique challenges and objectives, delivering bespoke solutions that address their specific needs.
Driven by innovation and a commitment to excellence, STIC SOFT E-SOLUTIONS is dedicated to staying at the forefront of technological advancements. By embracing emerging technologies and adopting agile methodologies, the company remains agile and adaptable in an ever-evolving digital landscape.
As businesses continue to navigate the complexities of the digital age, STIC SOFT E-SOLUTIONS stands ready to partner with them on their journey towards success, providing the expertise and support needed to thrive in today's competitive market.
there will be no banana left
A control using ActiveX technologies. An ActiveX control
can be automatically downloaded and executed by a Web
browser. ActiveX is not a programming language, but rather
a set of rules for how applications should share
information. Programmers can develop ActiveX controls in a
variety of languages, including C, C++, Visual Basic, and
Java.
24000
2 and half day.
43
810
24.
exp: 0 is formed by multiplying 5 with 2. so first we find
how many 5’s and 2’s are there in 100!.
No of 5’s : 100/5=20/5=4/5.
20 +4 =24.
No of 2’s : 100/2=50/2=25/2=12/2=6/2=3/2=1/2.
50 +25 +12 +6 +3 +1.
It has 24 5’s and 2’s.
so the no. of zeros=24.
In the example first we have to find the area of the field
we have given the following values ,
cost of fencing per meter = Rs 1.50
Diameter of circular field = 28
We have to find the area , a = ?
We know that,
Area = 2 π r
= 2 x 22/7 x 14
= 2 x 22 x 2
= 44 x 2
= 88 sq. m
So, area of circle is 88 sq.m
Now just multiply it with 1.50
cost of fencing = 88 x 1.50
= Rs. 132
So, the cost of fencing the circular field is Rs. 132
I have been teaching some students for 1 year.
Put switch 1 on and leave it on for 2 minutes, then switch it off.
Put switch 2 on and leave it on, then walk into the room.
If the light is on, the answer is switch 2.
If the light is off but the bulb is warm when you feel it, the answer is switch 1.
If the light is off and the bulb is cold when you feel it, the answer is switch 3.
a)0
b)206
c)0
d)250
e)39
f)92
Balls- B1, B2, B3, B4, B5, B6, B7, B8, B9.
Group1 – (B1, B2, B3), Group2 – (B4, B5, B6), Group3 – (B7, B8, B9)
Now weigh any two groups. Group1 on left side of the scale and Group2 on the right side.
When weighing scale tilts left – Group1 has a heavy ball or right – Group2 has a heavy ball or balanced – Group3 has a heavy ball.
Lets assume Group 1 has a heavy ball.
Now weigh any two balls from Group1. B1 on left side of the scale and B2 on right side.
When weighing scale tilts left – B1 is the heavy or tilts right – B2 is the heavy or balanced – B3 is the heavy.
16.8 sec