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Ques:- A starts from a place at 11.00 am and travels at a speed of 4 kmph , B starts at 1.00 pm and travels with speeds of 1 kmph for 1 hr , 2 kmph for the next hr , 3 kmph for the next hr and so on. At wht time will B catch up with A ?
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Ques:- A school has 30% students from Maharashtra .Out of these 20% are Bombey students. Find the total percentage of Bombay?
Recent Answer : :
66.66%
Ques:- Newton Rapson method is to find ?
Recent Answer : :
to find the root of f(x) = 0;
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Ques:- The sum of the squares of two consecutive positive integers exceeds their product by 91. Evaluate the integers?
Ques:- A and B can do a work in 12 days, B and C in 30 days and C and A in 36 days. In how many days will the work be completed, if all three of them work together?
Ques:- 5 men or 8 women do equal amount of work in a day. a job requires 3 men and 5 women to finish the job in 10 days how many woman are required to finish the job in 14 days.
Recent Answer : :
Lets assume total LCM(5,8) = 40units.
As, 5 men or 8 women do equal amount of work in a day,
1 Man does 8units/day and 1 Woman does 5units/day.
3M and 5W in 10 days do (3*8 + 5*5)*10 = 490units
To do 490 units in 14 days, number of Women required = 490/(14*5) = 7
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Recent Answer : :
Profit ratio will be : 4:5:6
5x=150
X=300
X share is 1200
Y share is 1800
Difference will be = x-y =600
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Recent Answer : :
4%
Ques:- The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?
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Ques:- Pipes P and Q would fill a cistern 18 and 24 minutes respectively. Both pipes being opened, find when the first pipe must be turned off so that the cistern may be just filled in 12 minutes?
Recent Answer : :
P’s one min work=1/18
Q’s one min work=1/24
P’s x min work+Q’s 12 min work = tank fully filled ( 1 )
x(1/18)+12(1/24)=1
x=9 min
Ques:- Find out the wrong number in the series:
40960, 10240, 2560, 640, 200, 40, 10
40960, 10240, 2560, 640, 200, 40, 10
A. 40
B. 200
C. 640
D. 2560
Recent Answer : :
200
the answer is At 9:48 PM
At 1:00 pm the difference between A & B = 8 km
after 2:00 pm ………………. = 11 km (as B’s speed
is 1 and A’s 4 km, then eqv speed=(4-1)=3 km)
After 3:00………………….. = 13 km (as B’s speed 2 km)
After 4:00………………….. = 14 km
after 5:00………………….. = 14 km (A’s speed= B’s
speed)
after 6:00………………….. = 13 km
after 7:00………………….. = 11 km
after 8:00………………….. = 8 km
after 9:00………………….. = 4 km
and now the eqv speed is= (9-4) =5 km/hr;
and the renaming distance is 4 km;
then, time=(60*4)/5=48 min;
then the meeting time is=9:00+48 min=9:48 pm;