- Sandalwood engineering & ergonomics General Aptitude Interview Questions
- Sandalwood engineering & ergonomics Trainee Interview Questions
- Sandalwood engineering & ergonomics Personal Questions round Interview Questions
- Sandalwood engineering & ergonomics HR Interview Questions
- Sandalwood engineering & ergonomics Lead Interview Questions
Total marbles are 15
Blue and yellow are 5
Probability is 5/15
Now as per question, Kamal invested for 12 months and Sameer invested for 7 months.
So, Kamal:Sameer=(9000×12):(8000×7)
=108.56=27:14
Sameer ratio in profit will be =6970×4114=Rs.2380
D
270
I’m the capable of what u expect from me and you should say what is the tallent u have which is used for that company…🥰
A
After the mixing, 1lt of the mixture has 0.8lt of milk and 0.2lt of water. 1lt of milk costs Rs.12 so 0.8lt of milk costs 0.8 x 12 = 9.6
He sells the mixture at Rs.15,
so profit%=(15-9.6)/9.6 x 100 = 56.25%
Soldier have to move 0.75 miles to West and then 0.375 miles to South to reach the camp.
How:-
Firstly soldier moving 1 mile to East from camp and then 1/2 miles= 0.50 miles to North .
Then it is moving 1/4 miles =0.25 miles to west
And then 1/8 miles =0.125 miles to South
Now we just have to count the difference and minus the value of camp to East with the value of North to west = 1mile – 0.25miles(1/4) = 0.75 miles
Same case with north and south = 0.50 miles(1/2) – 0.125 miles(1/8) = 0.375 miles
Hence proves to return camp the soldier have to move 0.75 miles to west and 0.375 miles to south
Let speed of stream be v mph
Then,
36/(10-v) = 1.5hr + 36/(10+v)
On solving, we get speed of stream as v = 2mph.
Fathers before age=3*before sons age—-(1)
After 2.5 years..
Fathers before age+2.5 years =2.5*sons age—-(2)
Substitute (1) in (2),
3*sons before age+2.5 years=2.5*sons age
0.5*sons age=2.5 years
Sons before age=5years
So current age after 2.5 years,
Sons before age+2.5 =5+2.5=7.5 years
The number of ways of selecting a group of eight is
5 men and 3 women=5C5×6C3 =20
4 men and 4 women=5C4×6C4 =75
3 men and 5 women=5C3×6C5=60
2 men and 6 women=5C2×6C6=10
Thus the total possible cases is 20+75+60+10=165.