Ques:- If I walk at 3 kmph, I miss the train by 2 min, if however, I walk at 4 kmph. I reach the station 2 min before the arrival of the train. How far do I walk to reach the station?
Recent Answer : Added by Admin On 2022-09-29 16:36:42:
answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x+602) hrs and
Time needed to reach the station at 4 km/hr = (4x+602) hrs But 3x+301=4x−301⇒3x−4x=−302=151
⇒124x−3x=151⇒12x=151⇒x=1512=54 km
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Ques:- In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class? (1) Data inadequate (2) 20 (3) 25 (4) 30 (5) None of these
Recent Answer : Added by Admin On 2020-05-17 12:03:57:
let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer
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A. 15
B. 30
C. 40
D. 45
Recent Answer : Added by Vijay Vinod On 2022-09-16 14:52:15:
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
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Recent Answer : Added by Evelyn Asumadu On 2021-09-22 16:57:03:
answer :
Let the distance which I walk to the station be x km Then Time needed to reach the station at 3 km/hr = (3x+602) hrs and
Time needed to reach the station at 4 km/hr = (4x+602) hrs But 3x+301=4x−301⇒3x−4x=−302=151
⇒124x−3x=151⇒12x=151⇒x=1512=54 km