Reverie power & automation engineering ltd. Interview Questions, Process, and Tips

Ques:- ABOUT PAST EXPE. & REASON OF JOB CHANGE
Ques:- If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?
Ques:- Find the least number with which 16200 should be multiplied, to make it a perfect cube.
Recent Answer : Added by Atif On 2022-12-05 16:13:24:

2

Ques:- A man pushed his car to a hotel and lost his fortune. What happened?
Ques:- Can u stay awake in the night?
Ques:- A man ate 100 bananas, each day eating 6more than the previous day. How many bananas did he eat on the first day.
Ques:- Aman started a business investing Rs.70,000. Rakhi hoined him after six months with an amount of Rs.1,05,000 and Sagar joined them with Rs.1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business?
A. 7 : 6 : 10
B. 12 : 15 : 16
C. 42 : 45 : 56
D. Cannot be determined
Recent Answer : Added by narendra On 2022-09-18 09:02:34:

b

Ques:- Is it possible to view the contents of my laptop on my tv and if so, how do I do it?Laymans language please.CheersDave
Ques:- A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is?
Recent Answer : Added by Shitoshe Wangatia On 2021-12-11 15:07:20:

Simple interest Formula:
A=P(1+rt)
Therefore,
815=P(1+3r)
P+3r=815

854=P(1+4r)
P+4r=854
Solve the sums using Elimination method.
P+4r=854
P+3r=815
r=39.
Toget Principal
P+4r=854
P+4*39=854
P=854-117
P=698

Ques:- The number of prime factors in the expression (6)10 x (7)17 x (11)27 is
A. 44
B. 54
C. 64
D. 71
Recent Answer : Added by Rahul Kumar Tiwary On 2021-11-13 11:02:13:

610 × 717 × 1127
= (2 × 3)10 × 717 × 1127
= 210 × 310 × 717 × 1127
Number of prime factors in the given expression
= (10 + 10 + 17 + 27)
= 64

Ques:- Why are you leaving that company?
Ques:- What will come in place of the question mark (?) in thefollowing sequence? ARRANGEMENTS, RRANGEMENT, RANGEMEN, ?, NGEM
A. RANGEME
B. ANGEME
C. ANGEMENT
D. NGEMEN
E. None of these
Recent Answer : Added by Admin On 2020-05-17 12:03:39:

( b ) ANGEME

Ques:- Four sisters- Rima, Seema, Uma and Shama are playing a game such that the loser doubles the money of each of the other players from her share. They played four games and each sister lost one game in alphabetical order. At the end of fourth game, each sister has Rs. 32. Who started with the lowest amount?
Ques:- Why do you want to work with IBM?
Ques:- How do you feel about the working hours from 9 to 5?
Ques:- You have 4218 no of balls. put 1 balls at top layer 3 at 2nd top layer then 6 and then 10 … Continue in this way. How many layers are possible.?
Recent Answer : Added by xyz On 2021-07-31 16:35:47:

211

Ques:- Why am I not using a vodafone no. when I am about to join vodafone?
Ques:- What was the last seminar you attended? How did you apply this new-found knowledge towards your work?
Ques:- A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Ques:- A football team played 60 matches out of which 30% were won by them. If they start winning all the next matches after how many matches will the average winning rate be 50% ?
Recent Answer : Added by Suman On 2021-10-07 15:41:23:

Matches played: 60.
Matches won: 30% of 60 => (60*(30/100)) = 18 matches.
Iterative approach:
On adding 1 to matches played and matches won, on every iteration until the win percentage gets to 50. So
19 / 61 = 0.3114754098360656
20 / 62 = 0.3225806451612903
21 / 63 = 0.3333333333333333
22 / 64 = 0.34375




Similarly,
41 / 83 = 0.4939759036144578
42 / 84 = 0.5

So, after 60th match 24 more matches has to be played and won to get 50% average winning rate.

Ques:- Why there are so many job changes in your career
Ques:- Find the simple interest on Rs.500 for 9 months at 6 paisa per month?
Recent Answer : Added by Shravan On 2021-08-04 15:54:04:

Answer:270
Explanation: Formula is SI= P*R*T/100
Where P is principal amount
R is Rate
T is Time
So, SI= 500*6*9/100
i.e SI= 27000/100
SI= 270

Ques:- A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Ques:- My personal Information
Ques:- What you have learn from your MBA?
Ques:- WHY COMPANY SHOULD SELECT YOU FOR THIS POST ?
Ques:- About your qualifications and expiriance
Ques:- You have given 12 balls of identical shape and a weighing compares. There is one ball defective among them. How will you find out the defective one and whether it is light or heavy in less number of weighing.
Ques:- Give the detailed description about the final year project(as I did MCA)?
Ques:- In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class? (1) Data inadequate (2) 20 (3) 25 (4) 30 (5) None of these
Recent Answer : Added by Admin On 2020-05-17 12:03:57:

let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer

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Devendra Bhardwaj With a decade of experience as a Job Hiring Expert, I am a results-driven professional dedicated to elevating recruitment strategies. My expertise lies in navigating the dynamic landscape of talent acquisition, employing innovative approaches to attract, assess, and secure top-tier candidates. I excel in optimizing hiring processes, leveraging cutting-edge technologies, and fostering collaborative relationships with stakeholders. A keen understanding of industry trends allows me to stay ahead, ensuring a competitive edge in securing the best talent for your organization. I am passionate about connecting the right people with the right opportunities and thrive in creating impactful, streamlined recruitment solutions.

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