Powerchina huadong engineering corporation limited Interview Questions, Process, and Tips

15

“Since I’ve been working and gaining experience to get into this company, I’d like to stay a long time if I’m offered the job, since this is where I want to be. “ “As long as there’s a lot of work to do, then I’d be happy to stay for a long time. Since I’m a busybody, I like to being productive most of the time.”

17 secs

Ans-44
4x+8=6Y
5X=5Y
X=Y
FROM EQ 1
2X=8
X=4
6Y+5Y=11*4=44

Total marbles are 15
Blue and yellow are 5
Probability is 5/15

X-340 = X x 4 x 8/ 100

100X – 34000 = 32X
68X = 34000
X = 34000/68
X= 500.

Ans. 175
Relative speed in m/s=40-22=18X5/18=5m/s
Total distance=125+x m
T=1min=60 s
D=sXt
125+x=5X60
x=175

Perimeter of semi circular = πr+2r

Where r is radius , π = 22/7

πr+2r= 144 (given)

(22/7)r +2r = 144

22r+14r = 144*7 (multiply both sides by 7)

36r = 144*7

r= 144*7/36 = 28

radius =28 cm

Area =( 1/2)πr^2

Area=( 1/2 )*(22/7)*28*28

= 1232cm^2
Ans : area is 1232 cm^2

Here is the solution to the given version of the puzzle (9 balls, one is heavier, need to identify oddball), where we label the balls A, B, …, I:

1. Weigh ABC versus DEF.

Scenario a: If these (1) balance, then we know the oddball is one of G, H, I.

2. Weigh G versus H.

Scenario a.i: If these (2) balance, the oddball is I.

Scenario a.ii: If these (2) do not balance, the heavier one is the oddball.

Scenario b: If these (1) do not balance, then the oddball is on the heavier side. For simplicity, assume the ABC side is heavier, so the oddball is one of A, B, C.

2. Weigh A versus B.

Scenario b.i: If these (2) balance, the oddball is C.

Scenario b.ii: If these (2) do not balance, the heavier one is the oddball.

answer is maximum of 2.

810

8days

ans: 40
6/3*12/3*15/3=40

Total number of pairs is NC2^{N}C_2NC2​. Number of pairs standing next to each other = N. Therefore, number of pairs in question = NC2^{N}C_2NC2​ – N = 28/2 = 14. If N = 7,
7C2​ – 7 = 21 – 7 = 14….
N =7