Petro IT Interview Questions, Process, and Tips

31
cos
434-403=31
465-434=31

Ans: 60 kph

Suppose Person meets the train everyday at 3 PM at Station A.

His speed is 12kph.

So normally he reaches 5 km before the meeting point (pt B) at (5/12 hr = 25 min before) 2:35PM.

But if he is late by 30 min, then he will reach that point (pt B) by 3:05 PM.

Train is traveling at its normal speed so it covers the distance of 5 Km in 5 min starting from Station A and reaches the meeting point (pt B) at 3:05 PM.

So speed of the train is 5KM/5min = 60 kph.

9 and 16

Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.

1052

FYI

4%

Explanation:

Let E1 be the event of drawing a red card.

Let E2 be the event of drawing a king .
P(E1 ∩ E2) = P(E1) . P(E2)
(As E1 and E2 are independent)
= 1/2 * 1/13 = 1/26

just will draw the line first and then draw three concentric circles

Solution:

As given, we have,

The cost of one pen = 36 Rs.

So, the cost of 15 pens = 36 × 15 = 540 Rs.

The cost of one book = 45 Rs.

So, the cost of 12 books = 45 × 12 = 540 Rs.

The cost of one pencil = 8 Rs.

So, the cost of 10 pencils = 8 × 10 = 80 Rs.

Now,

the cost of each eraser is 40 Rs. less than the combined costs of pen and pencil.

So,

Combined costs of pen and pencil = 36 + 8 = 44 Rs.

Cost of one eraser = 44 – 40 = 4 Rs.

So, the cost of 5 erasers = 4 × 5 = 20 Rs.

Hence,

The total amount spent is

Hence, the total amount spent is 1180 Rs.

These both ans are wrong Instead of cutting it vertically we cut it horizontally. we got 2 equal halves.

sample space=36
prob of one of the dice getting face 6
i.e n={(1,6)(2,6)(3,6)(4,6)(5,6)(6,1)(6,2)(6,3)(6,4)
(6,5)(6,6)}=11
p=n/s
p=11/36
ans:11/36

c

Answers as expected

C