Oxford analytica Interview Questions, Process, and Tips

Three man’s on day work = 1/6+1/7+1/8=73/168
three man’s can complete the work in 1/73/168 days
= 168/73 days
Now if they works together fro the alternet days they will
complete the worksin 2*168/73 days
(If three mans working for the alternate days then work
completion time will be doubbled)

21

The answer cannot be determined as there is a particular formula where the consecutive numbers start.

I would say everyone has blind spots, and i would too. And that is why I believe in teamwork because when you are a team, you can point out other people’s blind spots and they will do the same for you.

let A goes up and B comes down.
assume A takes 1 step in 1sec.
hence,B takes 5 steps in 1sec.
50 steps ll be moved by A in 50/1=50secs
125 steps ll be moved by B in 125/5=25 secs
hence speed of escalator=(difference of no of
steps)/(difference of time)
speed=(125-50)/(50-25)= 3 steps/sec
hence during upward journey of 50secs by A,total steps=50 by
A and 150 by escalator..total=150+50=200
during downward journey of 25 secs by B,total steps=125 by B
and 75 by escalator..total=125+75=200steps.
ANS:200 steps

time (dist covrd by husband) (dist covrd by wife)
0.5hr 20 miles 0 miles
1 hr 40 miles 25 miles
1.5 hr 60 miles 50 miles
2 hrs 80 miles 75 miles
2.5 hrs 100 miles 100 miles
Therefore wife catches up after 2.5 hrs..

friendly environment, supportive colleagues and place where i’ll have to work.

Let A=5x,B=3x,C not given so consider C=x
In triangle total angle=180°
A+B+C=180°
5x+3x+x=180°
9x=180°
X=180°/9
X=20°
A=5(20)=100°
B=3(20)=60°
C=20°
Therefore A=100° is the largest angle
Ans: 100°

The greatest number that will divide 187, 233 and 279 leaving the same remainder in each case.

To find : The number ?

Solution :

First we find the difference between these numbers.

The required numbers are

233-187=46

279-233=46

279-187=92

Now, We find the HCF of 46 and 92.

Therefore, The required largest number is 46.

B

19

If Vijay gives ‘x’ marbles to Ajay then Vijay and Ajay would have V – x and A + x marbles.
V – x = A + x — (1)
If Ajay gives 2x marbles to Vijay then Ajay and Vijay would have A – 2x and V + 2x marbles.
V + 2x – (A – 2x) = 30 => V – A + 4x = 30 — (2)
From (1) we have V – A = 2x
Substituting V – A = 2x in (2)
6x = 30 => x = 5.