Ques:- A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?
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Ques:- A person needs 6 steps to cover a distance of one slab. If he increases his foot length (step length) by 3 inches, he needs only 5 steps to cover the slabs length. What is the length of the each slab
Recent Answer : :
90 inches
Slab = 6(x) where x is each step
Slab = 5(x + 3)
6(x) = 5(x + 3)
6(x) = 5(x) + 15
x = 15 inches
So 6(x) = 6(15) = 90
Check: 5( x + 3) = 5(18) = 90
Slab size is 90 inches
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Recent Answer : :
sorry the above ans was typed by mistake the correct ans is…..
1027.05 ? 314.005 + 112.25 = ?
ans:
1027.05 – 314.005 + 112.25 = 825.295
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4. Annie Besant
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6″
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7500
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Recent Answer : :
A die is thrown twice n(s)=36
The probability of getting same number is (1,1)(2,2)(3,3)
(4,4)(5,5)(6,6) i.e n(A)=6
Ans. P(A)=n(A)/n(s)
= 6/36
=1/6.
So, The Answer is 1/6
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A. Kathak dancer
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Recent Answer : :
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Ques:- There N stations on a railroad. After adding X stations on the rail route 46 additional tickets have to be printed. Find N and X
Recent Answer : :
Each PAIR of stations means a PAIR of tickets (A to B and B to A)
2(old stations)(new stations) + 2(new stations)(new stations – 1) = 46
(N * X) + (X * (X – 1)) = 23
factoring ___ X (N + X – 1) = 23
23 is a prime number with only two factors, 1 and 23
so N = 23 and X = 1
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A. 32425
B. 32452
C. 34522
D. 32542
Recent Answer : :
d
– While the train is moving, the jogger will also be running in the same direction.
– for the head(engine) of the train to get to the current position of the jogger 240m away, it will take:
45km/hr => 12.5m/s => 240/12.5 = 19.2 seconds.
– But in the same period of time, the jogger will still be running and will have moved to a new location by: 9km/hr => 2.5m/s => 2.5 * 19.2 = 48m
To get to the new location at the speed of 12.5m/s will take the train:
48/12.5 = 3.84sec
In this additional time, the jogger will move forward by:
3.84 * 2.5 = 9.6m
at a speed of 12.5m/s, it will take the train less than a second to cover the additional 9.6m
If we add the distance the jogger will cover in 1 second to 9.6, it is still less than what the train can cover per second. let us see (9.6 + 2.5 = 12.1)
Therefore, the head of the train will pass the runner at approximately: 19.2 + 3.84 + 1 => 24.04 seconds.
For the train to completely pass the runner, it will need its whole length of 120m to be in front of the runner.
This will take an additional (9.6 + 2) seconds.
Therefore for the length of the train to be ahead of the runner it will take approx. 35.65 (24.04 + 9.6 + 2) seconds