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Ques:- 1) In a club there are certain no. of males and females. If 15 females are absent then no. of males will be twice that of females. If 45 males are absent then female strength will be 5 times that of males. Find no. of males actually present.
Recent Answer : Added by Admin On 2020-05-17 12:01:55:
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.
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Ques:- 98th term of the infinite series 1, 2, 3, 4, 1, 2, 3, 4, 1, 2, …… is
A. 1
B. 2
C. 3
D. 4
Recent Answer : Added by Hemlata vasava On 2022-08-14 16:39:47:
A, b
Ques:- The least number should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is
A. 3
B. 13
C. 23
D. 33
Recent Answer : Added by Shahram Hakimi On 2022-08-14 18:02:57:
23
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Ques:- A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
Recent Answer : Added by Anonymous On 2021-08-14 13:06:13:
Let:
1. speed of boat in still water = x
2. speed of stream = y;
Then net speed of boat upstream = x – y = 16km / 4 h = 4kmph
Net speed of boat downstream = x + y = 16 / 2 = 8kmph
Now solve for x to get x = 6kmph in still water.
Ques:- In a certain code, MONKEY is written as XDJMNL. How is TIGER written in that code?
Recent Answer : Added by Chuks On 2021-09-02 08:08:05:
MONKEY=YEKNOM then each letter is moved backward =XDJMNL so for TIGER=REGIT the each of the reversed letters are moved backward=QDFHS
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Ques:- During a given week A programer spends 1/4 of his time preparing flow chart, 3/8 of his time coding and the rest of the time in debugging the programs. If he works 48 hours during the week , how many hours did he spend debugging the program.
Recent Answer : Added by Admin On 2020-05-17 12:01:34:
Here is the ans with explanation…..
Just divide 48 hours into 8 parts…
for flowchart its 1/4 so it is 2/8 = 12hours
For Coding it is 3/8 = 18 hours
the rest is again 3/8 = 18 hours for debugging..
Ques:- The average of first 10 odd numbers is?
Recent Answer : Added by nani Reddy On 2021-08-05 17:11:28:
first 10 odd num are 1,3,5,7,9,11,13,15,17,19
sum=100
avg=100/10
avg of 10 odd num =10
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Ques:- A certain type of mixture is prepared by mixing brand A at Rs.9 a kg. with brand B at Rs.4 a kg. If the mixture is worth Rs.7 a kg., how many kgs. of brand A are needed to make 40kgs. of the mixture?
Recent Answer : Added by Admin On 2022-09-29 17:39:56:
Answer:
24
Step-by-step explanation:
A + B = 40.
And at Rs 7 a kg for 40 kg, you want a total of Rs.280.
So the second equation is 9A + 4B = 280
From the first equation: B = 40 – A
and sub into the second equation:
9A + 4(40-A) = 280
9A + 160 – 4A = 280
5A = 120
A = 24.
And you should check: B should equal 40-24 = 16. Check with the final equation: 9*24 + 4*16 = 216 + 64 = 280. So it works.
Your answer, of course, is A = 24
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A. Raveena Tandon
B. Sunil Shetty
C. Bobby Deol
D. Ayesha Zulka
Recent Answer : Added by Suresh On 2022-01-16 17:18:07:
Sunil Shetty
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Ques:- The day on 5th March of a year is the same day on what date of the same year?
A. 5th August
B. 5th October
C. 5th November
D. 5th December
Recent Answer : Added by narendra On 2022-09-18 09:03:34:
d
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Ques:- 2598Successive discounts of 20% and 15% are equal to a single discount of (a) 30%(b) 32% (c) 34% (d) 35% (e) 36
Let the number of males be given the name M.
Let the number of females be given the name F.
If 15 females are absent, then M will be twice that of
present females.
This means that M = 2 * (F – 15)
M = 2 * F – 30.
or 2 * F – M = 30.
Now if in addition to the 15 females being absent, we also
have 45 males being absent,
then this gives the equation,
(F – 15) = 5 * (M – 45)
which simplifies to
F – 15 = 5 * M – 225
5 * M – F = 210
Pulling the equations together, we get
5 * M – F = 210
-M + 2 * F = 30
Multiply the first equation by 2, and keep the second
equation as is.
10 * M – 2 * F = 420
– M + 2 * F = 30
Add the equations.
9 * M = 450
M = 50
Verify answer.
Calculate F
from – M + 2 * F = 30
-50 + 2 * F = 30
2 * F = 30 + 50
F = 40.
If 15 females are absent, then number of males will be twice
that of females.
40 – 15 = 25.
50 = 2 * 25. Confirmed.
If also 45 males were absent, then female strength would be
5 times that of males.
Female strength is 25 due to the 15 females being absent.
50 – 45 = 5.
25 = 5 * 5. Confirmed.