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Bus started at 8:00
it travelled with 18mph…
distance of destination is 27 miles…
we know velocity=(distance)/time
i.e., time=27/18hours=3/2hours=90 min…
i.e., the bus reached destination at 9:30
the bus stayed for 30 min…
so the bus started return journey at 10:00
now the bus returned with velocity 18 + (18/2)=27mph
the taken to the bus to travel = 27/27=1 hour = 60 min…
so bus would be returned on 11:00…
665
red
251
30%
suppose the area is 100 and it was increased by 69%, then
the area is 169 which it indicates the side of the square
is 13.. which means 30% increase in its side.
Both simultaneously because sales is the revenue generation team which is necessary for the commercial growth of the company whereas customer loyalty is again important for a company to go for long-term growth which is why good and satisfactory customer experience is necessary.
The answer is A)
y1 = 62 Rs/kg
y2 = 72 Rs/kg
y = 64.5 Rs/kg
y2 – y1 = 10 Rs/kg
The distance between the y and y1 is
y – y1 = 64.5 – 62 = 2.5
x1 = (y – y1)/(y2 – y1) = 2.5/10 = 0.25
x2 = 1 – x1 = 1 – 0.25 = 0.75
The target price is calculated by the lever method.
x1 * y2 + x2 * y1 = 0.25 * 72 + 0.75 * 62.5 = 64.5
The ratio is of y1 to y2 is
0.75 : 0.25
Divide by both by 0.25
3 : 1
speed=mile/hour
.•. time taken to travel M miles is
So, time =distance/speed
=M/m/h
=Mh/m hrs
Let’s assume the length of each train is ‘L’ and the speeds of the two trains are ‘V₁’ and ‘V₂’ respectively.
When the trains are moving in the opposite direction, their relative speed is the sum of their individual speeds. The total distance they need to cover is the sum of their lengths. Since they cross each other completely in 5 seconds, we can set up the following equation:
(V₁ + V₂) × 5 = 2L
When the trains are moving in the same direction, their relative speed is the difference between their individual speeds. The total distance they need to cover is the difference between their lengths. Since they cross each other completely in 15 seconds, we can set up the following equation:
(V₁ – V₂) × 15 = 2L
Now, let’s solve these equations to find the ratio of their speeds.
From the first equation, we have:
(V₁ + V₂) × 5 = 2L
V₁ + V₂ = (2L) / 5
From the second equation, we have:
(V₁ – V₂) × 15 = 2L
V₁ – V₂ = (2L) / 15
Let’s add these two equations together:
V₁ + V₂ + V₁ – V₂ = (2L) / 5 + (2L) / 15
2V₁ = (6L + 2L) / 15
2V₁ = (8L) / 15
V₁ = (4L) / 15
So, the speed of the first train is (4L) / 15.
Now, let’s substitute this value back into the first equation to find V₂:
(4L) / 15 + V₂ = (2L) / 5
V₂ = (2L) / 5 – (4L) / 15
V₂ = (6L – 4L) / 15
V₂ = (2L) / 15
Therefore, the speed of the second train is (2L) / 15.
The ratio of their speeds is given by:
(V₁ / V₂) = ((4L) / 15) / ((2L) / 15)
(V₁ / V₂) = 4L / 2L
(V₁ / V₂) = 2
So, the ratio of their speeds is 2:1.
find out what is the problem and taking the bad out always works.
A. 14th
Ans alphabet = Q alphabet – 1
CHRONRD
500 ways
Given:
Speed of man downstream= 30/3=10km/h
Speed of man in upstream=18/3=6km/h
Speed of man in still water=1/2 (speed of upstream+ speed of down stream)
= 1/2 (10+6)
=1/2*16
=8km/h
30