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Ques:- Two trains are on same track and they are coming toward each other. The speed of first train is 50 KMs/h and the speed of second train is 70 KMs/h. A bee starts flying between the trains when the distance between two trains is 100 KMs. The bee first flies from first train to second train. Once it reaches the second train, it flies back to the second train ? and so on until trains collide. Calculate the total distance traveled by the bee. Speed of bee is 40 KMs/h. .
Recent Answer : Added by DK BOSS On 2021-07-15 09:17:12:
Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)
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Recent Answer : Added by Admin On 2020-05-17 11:59:59:
X = 1/2 * b*h
base incresed by 4 times & height
is devided by 2
X = 1/2 * 4b * h/2
X = h/4 * 4b
X = hb
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Recent Answer : Added by DK BOSS On 2021-07-21 15:27:21:
Slice the cake
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Recent Answer : Added by divya On 2022-11-14 17:04:19:
Alice — 3844
Liu —30976
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Recent Answer : Added by Sanjeevnaidu On 2022-09-02 17:04:42:
Let speed of stream be v mph
Then,
36/(10-v) = 1.5hr + 36/(10+v)
On solving, we get speed of stream as v = 2mph.
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Recent Answer : Added by Admin On 2020-05-17 12:01:58:
16 poles per min
48kmph=48000 meters per hr
=800 meters per min
800/50=16 poles per min
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A. 143
B. 221
C. 343
D. 823
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Recent Answer : Added by V Revanth Royal On 2021-08-16 15:51:28:
31yrs
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Recent Answer : Added by Admin On 2020-05-17 11:59:40:
1/4E(E decreses by 4 times)
Ques:- There are 20 poles with a constant distance between each pole A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole
Recent Answer : Added by Admin On 2022-09-29 16:26:22:
Let the distance between each pole be x m. Then, distance up to 12th pole = 11x m
∴ Speed = 11x22m/s
∴ Time to cover total distance up to 20th pole
= 19x×2411x
= 41.45 s
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Ques:- There is a room with a door (closed) and three light bulbs. Outside the room there are three switches, connected to the bulbs. You may manipulate the switches as you wish, but once you open the door you can't change them. Identify each switch with its bulb.
Recent Answer : Added by DK BOSS On 2021-07-30 16:27:15:
Turn on a switch and leave it for some ten minutes. Turn it off, turn a second one on and open the door and go into the room. The glowing bulb corresponds to second switch. The bulb that is hot corresponds to first switch, as it was turned on for ten minutes and have heated up. The cold and not-glowing bulb corresponds to the third switch
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Ques:- If instead of multiplying a number by 7 the number was divided by 7. What should be the percentage error?
Recent Answer : Added by Rushi Maralkar On 2023-04-27 17:34:11:
% error= (new no-actual no)/actual no *100
% error= [(x/7)-7x]/7x * 100
% error= 48x/49x * 100
% error= 0.9795*100=97.95
Ques:- A man was engaged on a job for 30 days on the condition that he would get a wage of Rs. 10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he gets Rs. 216 at the end, he was absent for work for … days.
Recent Answer : Added by Qhizer On 2021-08-11 07:22:47:
30 days of earning =300 rs
No of days he was absent = x
Equating the abv
300 – 10 x – 2 x = 216
After solving for x you will get 7days
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Recent Answer : Added by Sonali On 2020-11-17 15:27:47:
31
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Answer: 66.67 km approx.
Solution:
Let the first train A move at u km/h.
Let the second train B move at v km/h.
Let the distance between two trains be d km
Let the speed of bee be b km/h
Therefore, the time taken by trains to collide = d/(u+v)
Now putting all the known values into the above equation, we get,
u = 50 km/hr
v = 70 km/hr
d = 100 km
b = 80 km/hr
Therfore, the total distance travelled by bee
= b*d/(u+v)
= 80 * 100/(50+70)
= 66.67 km (approx)