Ques:- A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Recent Answer : Added by Admin On 2022-09-29 19:29:04:
Speed = (45×518)m/sec=252m/sec
Total distance covered = (360+140) m = 500 m.
∴Required time= 500×225sec = 40 sec.
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Ques:- A person’s present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old id the mother at present?
Recent Answer : Added by MAMIDI LIJITA SREE On 2023-01-21 17:36:34:
40
Ques:- Three men A, B, C plays Cards. If one loses the game he have to give Rs.3. If he wins the game he will gain Rs.6. If A has won 3 Games, B loses Rs.3, C wins Rs.12.What is the total no. of games played?
Recent Answer : Added by Admin On 2020-05-17 12:01:57:
8 games They played
A own 3 games = 18 Rs
B loss 3 Rs and own 1 games i,e 9(A own 3 Games)-6(B own
1 game)=3
c own 12 Rs and loss 4 games(A own 3+b own 1) and own 4
games i.e 24(own)-12(loss)
so totally A own 3 games
B own 1 game
c own 4 games
=8
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Ques:- A train 100 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is?
Recent Answer : Added by suhad On 2022-09-02 17:04:44:
32 Km/hr
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Ques:- Find the number that has a 5:1 ratio to the number 10?
Ques:- The tens digit of a two-digit number is two more than its unit digit. The two-digit number is 7 times the sum of the digits. Find the units digits?
Recent Answer : Added by Jay On 2022-08-14 16:35:32:
31
Ques:- There are two candles of equal lengths and of different thickness. The thicker one lasts of six hours. The thinner 2 hours less than the thicker one. Ramesh lights the two candles at the same time. When he went to bed he saw the thicker one is twice the length of the thinner one. How long ago did Ramesh light the two candles?
Recent Answer : Added by Naru Mani Chandan On 2022-03-18 09:18:12:
3 hours ago.
Thin candle melts 3/4 in 3 hours leaving 1/4
Where as in the same time thick candle melts 3/6 leaving 3/6 which is 1/2. Now thick candle is exactly twice than the thin candle.
Or via modeling:
We need to find time at which the length of the thin candle is half the thick candle. Let x be the time. Thin candle melts at 1/4 an hour and thick candle melts at 1/6 an hour. In x hours they melt at x/4 and x/6 respectively. What’s left will be 1 – x/4 and 1 – x/6. We need to find x at which :
2 * (1 – (x/4)) = 1 – (x/6)
This equation results in x = 3
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Ques:- In a certain code language, the word ENQUIRY is written as YRIUQNE. How will the word REQUIRE be written in the code language ?
A. QERUERI
B. REQUERI
C. ERIUQER
D. IREUQER
E. None of these
Recent Answer : Added by 9074743593 On 2021-07-28 15:08:31:
C
Ques:- Sum of two consecutive nos is 55, larger one is?
Recent Answer : Added by Elvince On 2022-05-17 09:08:57:
Let the firt number be n,
The largest number will be n+1
Their sum
n+n+1=55
2n+1=55
2n=54
n=27
Largest number =27+1=28
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Ques:- a survey of 100 students at new england college showed the following:7 take english,history and language,17 take english and history,15 take english and language,18 take history and language,48 take english, 49 take history,38 take language.draw a venn diagram and answer the questions how many students
A. take history but neither of the other two?
B. take english and history but not language?
C. take none of the three?
D. take exactly two of the three?
E. do not take a language? (explanation also needed pls)
Ques:- The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, Evaluate the area of the triangle ?
Recent Answer : Added by Tushar Singh On 2022-03-09 16:33:29:
As it is a right angled triangle so we know the hypotenuse must be 13 and 5 & 13 are base and height (in any order).
Area of triangle = 0.5* base * height = 0.5 * 5 * 12 = 30
Ques:- Find the greatest number which is such that when 697, 909 and 1227 are divided by it, the remainders are all the same?
Recent Answer : Added by Kavisha Chintamani On 2021-09-14 15:41:40:
3
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A. a) If no. is odd it is head, if no. is even it is tail
B. b) vice versa...
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Speed = (45×518)m/sec=252m/sec
Total distance covered = (360+140) m = 500 m.
∴Required time= 500×225sec = 40 sec.