Ques:- A bus started from the bus stand at 8 Am and after staying 30 minutes at a destination return back to the bus stand. The Destination is 27 miles from the bus stand . The Speed of the bus is 18mph . In the return journey the bus travells with 50% fast speed.At what time it is return to the bus stand ?
Ques:- if length of a rectangle is incr by 20% and width is decr by 20% then area
Recent Answer : :
we know,
area=b*h
b gets increased by 20% i.e (b+0.20b)
h gets decreased by 20% i.e (h-0.20h)
rewriting the equation(area=b*h),
area=(b+0.20b)*(h-0.20h)
area=b(1+0.20)*h(1-0.20)
area=b(1.20)*h(0.80)
area=b*h*(1.20)*(0.80)
area=b*h*(0.96)
i.e new area=0.96 times the original area
if 100% was the original area,it has decreased to 96%
so,100%-96%= 4%
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A. Rs. 45
B. Rs. 50
C. Rs. 55
D. Rs. 60
Recent Answer : :
45
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Recent Answer : :
Mohammad Gauri
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Recent Answer : :
25
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4
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156
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Recent Answer : :
4500 sal of jan
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Recent Answer : :
2*3(15+4)=114
114*1/2=57 rs
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Ques:- Person who dicided to go to weekend trip should not exceed 8 hrs driving in a day. Average speed of forward journey is 40 miles/hour . Due to traffic in sundays ,in return journey average speed is 30mph.How far he can select a picnic spot?
Recent Answer : :
Let the journey distance be : x miles
Now x/40+x/30=8 (time=distance/speed)
Solving this for x we get. x=960/7
therefore, x=137(approx)
(137.14 exact)
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Recent Answer : :
5x/4
Bus started at 8:00
it travelled with 18mph…
distance of destination is 27 miles…
we know velocity=(distance)/time
i.e., time=27/18hours=3/2hours=90 min…
i.e., the bus reached destination at 9:30
the bus stayed for 30 min…
so the bus started return journey at 10:00
now the bus returned with velocity 18 + (18/2)=27mph
the taken to the bus to travel = 27/27=1 hour = 60 min…
so bus would be returned on 11:00…