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7 months
let no. of boys not participating be x
then the no. of girls not participating = x+5
no. of boys : girls participating = 3:2
given no.of boys participating = 15
therefore, the ratio is now 15:y(say)
then 3:2 = 15 : x
on solving 3/2 =15/y ie.., 3y =30 we get y =10
hence no. of girls participating =10
therefore total no of students paricipating = 15+10=25
total no of students in class =60 given
hence no. of students not participating = 60-25=35
therefore x+(x+5)=35
2x=30
x=15
therfore no of girls not participating =15+5=20
therefore total no of girls in class = no of girls
participating + no of girls not participating
=10+20
=30 is the answer
I am looking for a qualified chartered accountant in my profile who is known for his excellence in the field.
32,7
3:4
3x:4x
3x+4x=420
7x=420
x=60
smaller number=3(60)=180.
Given y/x = 1/3, x+2y =10
3y=x
Then substitute x=3y in x+2y=10
3y+2y=10
5y=10
y=2
Then substitute y=2 in x=3y
x=3*2
x=6
: x=6, y=2
5c2*4c1/9c3 +5c3/9c3=25/42
Neice
my best friend name is chandrakala. she is try to job.
If both agree stating the same fact, either both of them speak truth of both speak false.
∴ Probability
=3/5×4/7+2/5×3/7=12/35+6/35=18/35
Answer is 45
First we need to subtract those reminders from the respective numbers, then we have to find the hcf of two numbers(numbers got from the subtraction) then you will get the answer.
So,
After subtraction you will get
3026-11 = 3015
5053-13 = 5040
HCF of these two numbers
5 | 3015 5040
3 | 603 1008
3 | 201 336
| 67 112
We can’t find a common diviser since 67 is a prime number
So the HCF = 5 * 3 * 3
= 45
5*3*3 = 45
800 yards
Assum that the lables are : mixture, apples and orange
we have to take out one fruit from the mixture basket an see:
if it’s an apple –
it means that this basket is filled with apples
and so, the third basket is mixture
and the second one is filled with oranges.
if it’s an orange –
it means that this basket is filled with oranges
and so, the second basket is mixture
and the third one is filled with apples.
Answer: 600m
Explanation:
Distance covered by Amar = 18/4.8 (1.6km) = 3/8(1600) = 600 m